Answer:
For a bilateral test the p value would be:
Step-by-step explanation:
Information given
n=225 represent the sample selected
X=87 represent the households with incomes below the poverty level
estimated proportion of households with incomes below the poverty level
is the value that we want to test
z would represent the statistic
represent the p value
System of hypothesis
We want to check if the true proportion is equal to 0.32 or not.:
Null hypothesis:
Alternative hypothesis:
The statistic is given bY:
(1)
Replacing we got:
For a bilateral test the p value would be:
Do this every day
1x1=
2x1
3x1
4x1
5x1
6x1
AND SO ON JUST DO TABLE BY TABLE
Answer: There are no real solutions
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
