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nika2105 [10]
3 years ago
12

Select the approximate values of x that are solutions to f(x) = 0, where f(x) = -8x^2 + 8x + 5.

Mathematics
1 answer:
sertanlavr [38]3 years ago
6 0
f(x)=-8x^2+8x+5\\\\f(x)=0\iff-8x^2+8x+5=0\\\\a=-8;\ b=8;\ c=5\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot(-8)\cdot5=64+160=224\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{224}\approx\sqrt{225}=15\\\\x_1\approx\frac{-8-15}{2\cdot(-8)}=\frac{-23}{-16}=1\frac{7}{16}\approx1.5\\\\x_2\approx\frac{-8+15}{2\cdot(-8)}=\frac{7}{-16}=-\frac{7}{16}\approx-0.5
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1 question for brain list :)
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8 0
3 years ago
What is the solution to the equation One-third (x minus 2) = one-fifth (x + 4) + 2? x = 12 x = 14 x = 16 x = 26
inessss [21]

Answer:

x = 26

Step-by-step explanation:

1 / 3 (x - 2) = 1 / 5 (x + 4) + 2

1/3x - 2/3 = 1/5x + 4/5 + 2

1/3x - 1/5x = 4/5 + 2/3 + 2

(5x - 3x)/15 = (12 + 10 + 30) / 15

2x / 15 = 52 / 15

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x = 52 / 2

x = 26

6 0
4 years ago
Given the polynomial function below, find F(-1). F(x) = -x ^3 - x ^2 + 1
steposvetlana [31]

Answer:

f(-1) = 1

Step-by-step explanation:

Given

f(x) = -x^{3}-x^{2} +1

Finding f(-1) means, we have to put -1 in the places of x in the function,

So, putting x=-1 in the function

f(-1) = (-1)^{3} - (1)^{2} +1

As the power 3 is odd, the minus will remain the same, while in the 2nd term minus will be eliminated due to even power. So,

=> -1-1+1

=> 1

Hence,

f(-1) = 1

7 0
3 years ago
Point P is located at (–3, –2). P is reflected across the x-axis to create P'. What quadrant is P' in?
Eva8 [605]
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(-2,-3) -> (2,-3)

You change the x-factor's sign. 

I hope this helps!
~kaikers

4 0
4 years ago
Does the line whose equation is 4/3 x + 8 pass through the point (9,20)
sergey [27]

Answer: yes

Step-by-step explanation: slope is 4/3 and y intercept is 8

m= Y-20/0-9

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4/3 x -9 = y-20

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Y=20-12

Y=8

5 0
3 years ago
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