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12345 [234]
3 years ago
7

Write an algebraic expression that represents the following statement: “7 less than the quotient of 5 and n" *

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0

\huge\boxed{\boxed{\bold{\frac{5}{n}-7}}}

\hrulefill

We'll start with the expression for the quotient of 5 and n, which means we'll use division:

\frac{5}{n}

Now we find 7 less than that, meaning we'll use subtraction:

\frac{5}{n}\bold{-7}

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Depenendent Event
DaniilM [7]

Answer:

.2

Step-by-step explanation:

first you add all the pencils up which is 12 next take the probably of taking out one of each pencil .4 for green .2 for black and .6 for yellow next you divide the probably for pulling 1 green bye 2 since your pulling out 2

8 0
2 years ago
Read 2 more answers
Pleaseeeeeee help mee
BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given  

                cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

                  cos( 3x - \frac{\pi }{3} )  = cos (\frac{\pi }{6} )

                      3x - \frac{\pi }{3}  =  \frac{\pi }{6}

                      3x - \frac{\pi }{3  } + \frac{\pi }{3}   =  \frac{\pi }{6} + \frac{\pi }{3}

                      3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}

                     x = \frac{\pi }{6}

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

<u><em>verification </em></u>:-

      cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

put  x = \frac{\pi }{6}

    cos( 3(\frac{\pi }{6})  - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

    cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} =  \frac{\sqrt{3} }{2}

Both are equal

∴The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

                     

4 0
2 years ago
If 3x + 4 = -5 what is the value of x2 - 4x?
Ratling [72]
Hope this helps you!!

4 0
3 years ago
Need help on this calculus
N76 [4]
\displaystyle\int\sin^3t\cos^3t\,\mathrm dt

One thing you could do is to expand either a factor of \sin^2t or \cos^2t, then expand the integrand. I'll do the first.

You have

\sin^2t=1-\cos^2t

which means the integral is equivalent to

\displaystyle\int\sin t(1-\cos^2t)\cos^3t\,\mathrm dt

Substitute u=\cos t, so that \mathrm du=-\sin t\,\mathrm dt. This makes it so that the integral above can be rewritten in terms of u as

\displaystyle-\int(1-u^2)u^3\,\mathrm du=\int(u^5-u^3)\,\mathrm du

Now just use the power rule:

\displaystyle\int(u^5-u^3)\,\mathrm du=\dfrac16u^6-\dfrac14u^4+C

Back-substitute to get the antiderivative back in terms of t:

\dfrac16\cos^6t-\dfrac14\cos^4t+C
4 0
3 years ago
Read 2 more answers
the question is in the picture, i need the weight of train a and b i’ll give the right answer brainlist :))
frez [133]

Answer:

a 106

b 92

Step-by-step explanation:

Hope this helps!

6 0
2 years ago
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