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umka21 [38]
3 years ago
13

Two angle measures in a scalene triangle are 77° and 62°. what is the measure of the third angle

Mathematics
1 answer:
quester [9]3 years ago
4 0
For any triangle, the three angles must add up to 180 degrees. So if you have two of the angles and want to find the third, make an equation, designating the unknown angle, x, to find the sum. It should look like this: 77+62+x=180. Now isolate the x-variable and you find the third angle to be 41 degrees
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Mr. Itol's assistant takes twice as long to complete a computer task as Mr. Itol. If it takes both experts 6 hours to complete t
Lesechka [4]
So, in order to solve this problem, I will set up an equation. First, let's make x= the # of hours it takes Mr. Itol to complete a computer task, and since his assistant takes twice as long, lets make 2x=the # of hours it takes the assistant to complete the task. We also know that it takes the two of them 6 hours to complete the task together. We can now set up the following equation: 

\frac{1}{2x} +  \frac{1}{x} =  \frac{1}{6}

Now, in order to be able to solve this, we have to find the least common denominator, and then we can cancel out the denominators to solve for the top part. The LCD=6x and the new equation becomes: 

\frac{3}{6x} +  \frac{6}{6x} =  \frac{x}{6x}

Now, we can get rid of the denominators, and we get:

3+6=x

So, x= 9

Now we know that Mr. Itol would take 9 hours to complete the task if he were to do it himself. To find how long it would take his assistant to complete the same task by himself, we just need to plug in the x-value into 2x:

2(9)=18

Therefore, your answer is that Mr. Itol would take 9 hours to do the job alone, while his assistant will take 18 hours (double the time) to do the job alone.

Hope this helps :) 










4 0
3 years ago
ABCDE and FGHJE are similar pentagons. If the perimeter of FGHJE is 7.3, what is the perimeter of ABCDE?
kiruha [24]
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4 0
3 years ago
Read 2 more answers
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Leona [35]

\dfrac{d}{dx}(\dfrac{\sin(3x)}{x})

First we must apply the Quotient rule that states,

(\dfrac{f}{g})'=\dfrac{f'g-g'f}{g^2}

This means that our derivative becomes,

\dfrac{\dfrac{d}{dx}(\sin(3x))x-\dfrac{d}{dx}(x)\sin(3x)}{x^2}

Now we need to calculate \dfrac{d}{dx}(\sin(3x)) and \dfrac{d}{dx}(x)

\dfrac{d}{dx}(\sin(3x))=\cos(3x)\cdot3

\dfrac{d}{dx}(x)=1

From here the new equation looks like,

\dfrac{3x\cos(3x)-\sin(3x)}{x^2}

And that is the final result.

Hope this helps.

r3t40

7 0
3 years ago
Read 2 more answers
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Nataly_w [17]

Answer: 32 is the answer

Step-by-step explanation:

6 0
3 years ago
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Greeley [361]
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sin20cos40 + cos20sin40 = sin(20+40) = sin60degree

= \frac{ \sqrt{3}}{ 2}
3 0
3 years ago
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