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3 years ago

Use the point-slope formula (if possible) to write an equation of the line given the following

Mathematics

1 answer:

uysha [10]3 years ago

8 0

Answer:

y = -5 (x+2)

Step-by-step explanation:

We can use the point slope form of a line

y-y1 = m(x-x1) where (x1,y1) is the point and m is the slope

y-0 = -5(x--2)

y = -5 (x+2)

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3 years ago

F(1)=7, F(n)= -4* f(n-1)+15 Find the first four terms

Virty [35]

First four terms are 7, -13, 67, -253

Solution:

Given that,

$f(1) = 7$

The formula to find nth term is given as:

$f(n) = -4 \times f(n-1) + 15$

We can find the first four terms by substituting n = 2, 3, 4

First term:

f(1) = 7

Second term:

Substitute n = 2

$f(2) = -4 \times f(2-1) + 15\\\\f(2) = -4 \times f(1) + 15\\\\Substitute\ f(1) = 7\\\\f(2) = -4 \times 7 + 15\\\\Simplify\\\\f(2) = -28 + 15\\\\f(2) = -13$

Third term:

Substitute n = 3

$f(3) = -4 \times f(3-1) + 15\\\\f(3) = -4 \times f(2) + 15\\\\Substitute\ f(2) = -13\\\\f(3) = -4 \times -13 + 15\\\\Simplify\\\\f(3) = 52+15\\\\f(3) = 67$

Fourth term:

Substitute n = 4

$f(4) = -4 \times f(4-1) + 15\\\\f(4) = -4 \times f(3) + 15\\\\Substitute\ f(3) = 67\\\\f(4) = -4 \times 67 + 15\\\\Simplify\\\\f(4) = -268+15\\\\f(4) = -253$

Thus first four terms are 7, -13, 67, -253

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3 years ago

Solve the quadratic equation by using a graphic approach. Round your answer to the hundredths place.

den301095 [7]

Answer:

x = 3.24, x = -1.24

Step-by-step explanation:

The standard form for a quadratic equation is $ax^2+bx+c=0$ . For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is $x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}$ .