S=number of 6 cent stamps
t=number of ten cen stamps
e=number of 8 cent stamps
w=number of 20 cents stamps=2
cost=500 cents
6s+10t+8e+20w=500
w=2 since two 20 cent stamps wer bought
6s+10t+8e+40=500
minsu 40 both sides
6s+10t+8e=460
divide both sides by 2 to simplify
3s+5t+4e+230
also
10 more 6 cent than 10 cent
s=10+t
8 cent stamps is 3 times 10 cent stamps
e=3t
sub
s=10+t
e=3t
3(10+t)+5t+4(3t)+230
30+3t+5t+12t=230
30+20t=230
minus 30
20t=200
divid 20
t=10
sub back
s=10+t
s=10+10
s=20
e=3t
e=3(10)
e=30
20 six cent
30 eight stamp
10 ten cent
2 twenty cent
Its (x+3)(x+4)=5 , the third one
Answer: x = -1/8
Step-by-step explanation:
Given the equation 9^x+1 - 13(3^x)+4=0
First, open the bracket, multiply 13 by 3
9^x+1 - 39^x+4=0
Combine like terms
9^x - 39^x +4 +1=0
40^x+5=0
Make x the subject
40^x=0 -5
40^x= -5
Divide both sides by 40
40^x/40=-5/40
x = -1/8
I hope this is clear, please mark as brainliest answer.
Answer:
4, 7, 10, 13, 16, 19, 22
Step-by-step explanation:
Not sure if there is more to this question but here is what I assume:
We want to find the first 7 terms of this equation given 3n+4
Assuming we are starting at 0 we plug 0 in for n.
3(0) + 4 → 4
So our first answer is 4
We continue by pugging in the next numbers after that to get to the first 7 terms
3(1) + 4 → 7
3(2) + 4 → 10
3(3) + 4 → 13
3(4) + 4 → 16
3(5) + 4 → 19
3(6) + 4 → 22
Answer:
47
Step-by-step explanation:
Sub in 5 for y:
7+5(3+5)
7+5(8)
7+40
47
