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tester [92]
3 years ago
8

A vendor bought 10 dozen eggs at the rate of rupees 22 oer dozen. Six of the eggs were rotten. He sold the remaining eggs at the

rate of rupees 2.50 per egg. Find the profit and loss.​
Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

hi I am new here in brainly

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Im very young and need help whats 2+2
Fynjy0 [20]

Answer:

4

Step-by-step explanation:

if you had 2 monkeys and another 2 monkeys and you put them in a pen together then you will have 4 monkeys in the pen

hope this helps :))

7 0
3 years ago
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$900,000 is what percent of $900,000?
USPshnik [31]
What type of question is this
8 0
2 years ago
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What steps would you use to plot (−3, −4, 0) in a 3-dimensional coordinate system?
eimsori [14]

Answer:

a. From the origin, move back 3 units and down 4 units

Step-by-step explanation:

Given:

The coordinates of a point in a 3-dimensional space is given as:

(-3, -4, 0)

The value of 'x' = -3

The value of 'y' = -4

The value of 'z' = 0

At the origin, the values of 'x', 'y', and 'z' are each equal to 0.

So, the coordinates of origin is (0, 0, 0). In order to reach the point (-3, -4, 0) from the point (0, 0, 0), we don't move along the z-axis as the 'z' value remains the same. We need to move along the 'x' and 'y' directions only.

Now, 'x' is equal to -3. Negative values of 'x' occur backwards from origin. So, we move back by 3 units. to reach the point (-3, 0).

Now, the value of 'y' is -4. Negative values of 'y' occur below the origin. So, we move down by 4 units to reach the point (-3, -4).

Therefore, the correct option is option (a)

A graph in 2 dimensional is shown in support of the answer.

8 0
3 years ago
+8+-9+-2 on a number line
Zarrin [17]
Hi there! I can help you! 8 + (-9) + (-2). When adding negative integers, you have to subtract. 8 - 9 is -1 and -1 - 2 is -3. You would have to start at 8 and go to the left 11 times to land on -3. The sum to the problem is -3.
3 0
3 years ago
5/6 = 1/3+d and x/x is a fraction
Alik [6]

\dfrac{1}{3}+d=\dfrac{5}{6}\qquad|-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1\cdot2}{3\cdot2}\\\\d=\dfrac{5}{6}-\dfrac{2}{6}\\\\d=\dfrac{5-2}{6}\\\\d=\dfrac{3}{6}\\\\d=\dfrac{3:3}{6:3}\\\\\boxed{d=\dfrac{1}{2}}

7 0
3 years ago
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