Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
I think it’s 6
Sorry if I’m wrong
Answer:
Scale factor for the drawing from actual park = 
Area of the actual park = 1200 cm²
Step-by-step explanation:
Length of the rectangular city park = 5 cm
Width of the rectangular park = 6 cm
Using scale factor 1 cm = 20 meters
Scale factor = 
Actual length = 5 × 20 = 100 meters
Actual width = 6 × 20 = 120 meters
Area of the rectangular park = length × width
= 100 × 120
= 1200 square meters
Therefore, Scale factor from actual length to the length in drawing = 1 : 20
Area of the rectangular park = 1200 square feet
Answer:
17 i think
Step-by-step explanation:
Answer:
bc is 26
Step-by-step explanation:
