Answer:
1. (d) First F, then D, then C
2. x=16, not extraneous
Step-by-step explanation:
1. Let's solve the given equation and see which steps we need:
Since the X is under a square root, let's raise both sides to their square value.
So we get: 6x + 4 = 64
Next step is to isolate the x factor, so we need to subtract 4 on both sides, to get:
6x = 60
Then to isolate x, we need to divide both sides by 6.
x = 10.
2. Solve for x. 
We'll first begin by isolating the square root on its side alone:
Then we'll raise each side to its square: x + 9 = 25
Isolate x, to get x = 16
Now, is that solution extraneous or not?
Let's enter 16 in the initial equation and find out:
It works, so the solution is not extraneous!
Let the weight of Paula's dog be x
Let the weight of Carla's dog be y
We know that the weight of Paula's dog is 3 times that of Carla's dog, therefore:
x = 3y ...........> equation I
We also know that the sum of the weights is 48 pounds, therefore:
x + y = 48 ............> equation II
Substitute with equation I in equation II:
3y + y = 48
4y = 48
y = 12 pouds
Substitute with the value of y in equation I:
x = 3(12) = 36 pounds
Based on the above calculations:
Paula's dog weighs 36 pounds
Carla's dog weighs 12 pounds
I'm going to say for this one it's going to be 46% Notice that the word percent has the word "cent", meaning a hundred. So "per hundred". We have 46 out of 100 here, so 46/100, and we can simplify to 23/50. Hope this helps.
What grade are you in and i can tell you what the asnswer is
