Answer:
see below
Step-by-step explanation:
<em>Which of the equations from part A represent adding two rational numbers?</em>
Equations A, C, E
<em>What hypothesis can you make about the sum of two rational numbers?</em>
The sum of two rationals will always be rational
<em>Will the addition result in a rational or an irrational number?</em>
Our hypothesis is that the result is always rational. This can be justified by the fact that the sum of two rationals a/b + c/d, where a, b, c, d are integers and bd≠0, is (ad+bc)/(bd), a rational, based on closure of integers for multiplication and addition.
<em>Which equations represent the sum of a rational and an irrational number?</em>
Equations B, F
<em>What hypothesis can you make about the sum of an irrational and a rational number?</em>
The sum of a rational and irrational number is always irrational.
Answer:
(-1,2)
Step-by-step explanation:
5 People can be chosen in 1287 ways if the order in which they are chosen is not important.
Step-by-step explanation:
Given:
Total number of students= 13
Number of Students to be selected= 5
To Find :
The number of ways in which the 5 people can be selected=?
Solution:
Let us use the permutation and combination to solve this problem
So here , n =13 and r=5 ,
So after putting the value of n and r , the equation will be
Answer:
Step-by-step explanation:
Integrating each term with respect to x, we get:
x^3 x^2
f(x) = 9--------- + 4------- - 4x + C
3 2
We are told that if x = 0, f(x) = -7, and so C must equal - 7.
The solution is
x^3 x^2
f(x) = 9--------- + 4------- - 4x - 7, or f(x) = 3x^3 + 2x^2 - 4x - 7
3 2
