The amount in account after 6 years is $ 3774.70904
<em><u>Solution:</u></em>
<em><u>The formula for amount when interest is compounded is:</u></em>
![A = p(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%20%3D%20p%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
Where,
A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per unit t
t = the time the money is invested or borrowed for
From given,
p = 3500
t = 6 years
![r = 1.26 \% = \frac{1.26}{100} = 0.0126](https://tex.z-dn.net/?f=r%20%3D%201.26%20%5C%25%20%3D%20%5Cfrac%7B1.26%7D%7B100%7D%20%3D%200.0126)
n = 12 ( since compounded monthly )
Substituting the values we get,
![A = 3500(1+\frac{0.0126}{12})^{12 \times 6}\\\\A = 3500(1+0.00105)^{72}\\\\A = 3500 \times 1.00105^{72}\\\\A = 3500 \times 1.078488\\\\A = 3774.70904](https://tex.z-dn.net/?f=A%20%3D%203500%281%2B%5Cfrac%7B0.0126%7D%7B12%7D%29%5E%7B12%20%5Ctimes%206%7D%5C%5C%5C%5CA%20%3D%203500%281%2B0.00105%29%5E%7B72%7D%5C%5C%5C%5CA%20%3D%203500%20%5Ctimes%201.00105%5E%7B72%7D%5C%5C%5C%5CA%20%3D%203500%20%5Ctimes%201.078488%5C%5C%5C%5CA%20%3D%203774.70904)
Thus the amount in account after 6 years is $ 3774.70904