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jolli1 [7]
2 years ago
13

Un vendedor de frutas tiene cierto número de mangos, vende 3/5 de ellos más dos mangos; luego vende 1/3 de los restantes más dos

mangos, luego vende la mitad del saldo más un mango. Finalmente vende los 24 restantes, el número de mangos inicial empieza con la cifra
Mathematics
1 answer:
valkas [14]2 years ago
5 0

Respuesta:

200 mangos

Explicación paso a paso:

Dado :

Sea el número inicial de mangos = x

Primera venta:

3 / 5x + 2

Número a la izquierda = x - (3 / 5x + 2) = 2 / 5x - 2

Segunda venta:

1/3 (2 / 5x - 2) + 2 = 2 / 15x - 2/3 + 2

Cantidad restante:

2 / 5x - 2 - (2 / 15x - 2/3 +2)

2 / 5x - 2 - 2 / 15x + 2/3 - 2

0,2666666x - 3,3333

Tercera venta:

1/2 (0,2666666x - 3,3333) + 1 = 0,133333x - 1,666665 + 1

0.2666666x - 3.3333 - (0.133333x - 1.666665 + 1) = venta final

0,2666666x - 3,3333 - (0,133333x - 1,666665 + 1) = 24

0,2666666x - 3,3333 - 0,133333x + 1,666665 - 1 = 24

0,133333x - 2,666635 = 24

0.133333x = 24 + 2.666635

0,133333x = 26,666635

x = 26,666635 / 0,133333

x = 200.00026

x = 200 mangos

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What is the primary goal and secondary goal of the Fried Liver Opening in chess? <br />
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3 0
3 years ago
John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho
Margarita [4]

The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

^nC_r = \dfrac{n!}{r!(n-r)!}

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as ^2C_1.

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as ^4C_1.

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

=\ ^2C_1 \times ^4C_1\\\\=\ 8

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

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2 years ago
The midpoint M and one endpoint of JK are given. Find the coordinates of the other endpoint. J(7,2) and M(1,-2)
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Step-by-step explanation:

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7 + Xk/2 = 1

to get rid of the bracket, multiply all two sides by the denominator.

2(7 + Xk/2) = 1(2)

7 + Xk = 2

Xk = 2 - 7

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Yj + Yk/2 = Ym

2 + Yk/2 = -2

to get rid of the bracket, multiply all two sides by the denominator.

2(2 + Yk/2) = -2(2)

2 + Yk = -4

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Therefore the coordinates of point K is (-5,-6)

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Half a number is equal to 8
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Answer: 8=1/2x

Step-by-step explanation:

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