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jolli1 [7]
3 years ago
13

Un vendedor de frutas tiene cierto número de mangos, vende 3/5 de ellos más dos mangos; luego vende 1/3 de los restantes más dos

mangos, luego vende la mitad del saldo más un mango. Finalmente vende los 24 restantes, el número de mangos inicial empieza con la cifra
Mathematics
1 answer:
valkas [14]3 years ago
5 0

Respuesta:

200 mangos

Explicación paso a paso:

Dado :

Sea el número inicial de mangos = x

Primera venta:

3 / 5x + 2

Número a la izquierda = x - (3 / 5x + 2) = 2 / 5x - 2

Segunda venta:

1/3 (2 / 5x - 2) + 2 = 2 / 15x - 2/3 + 2

Cantidad restante:

2 / 5x - 2 - (2 / 15x - 2/3 +2)

2 / 5x - 2 - 2 / 15x + 2/3 - 2

0,2666666x - 3,3333

Tercera venta:

1/2 (0,2666666x - 3,3333) + 1 = 0,133333x - 1,666665 + 1

0.2666666x - 3.3333 - (0.133333x - 1.666665 + 1) = venta final

0,2666666x - 3,3333 - (0,133333x - 1,666665 + 1) = 24

0,2666666x - 3,3333 - 0,133333x + 1,666665 - 1 = 24

0,133333x - 2,666635 = 24

0.133333x = 24 + 2.666635

0,133333x = 26,666635

x = 26,666635 / 0,133333

x = 200.00026

x = 200 mangos

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