Given: segment PT || segment QS, segment PT ≅ segment QS, ∠T ≅ ∠S
Prove: ΔPQT ≅ ΔQRS
1 answer:
Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
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