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Tcecarenko [31]
3 years ago
12

Given: segment PT || segment QS, segment PT ≅ segment QS, ∠T ≅ ∠S Prove: ΔPQT ≅ ΔQRS

Mathematics
1 answer:
vfiekz [6]3 years ago
4 0

Segment PT || segment QS,                                  Given

segment PT ≅ segment QS,  

∠T ≅ ∠S

 

Angle TPQ = Angle SQR                      PR is a transversal  cutting parallel segments SQ and TP

                                                             So....it makes corresponding angles TPQ and SQR equal    

 

ΔPQT   ≅    ΔQRS                                ASA congruency

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