3 years ago

Given: segment PT || segment QS, segment PT ≅ segment QS, ∠T ≅ ∠S Prove: ΔPQT ≅ ΔQRS

Mathematics

1 answer:

vfiekz [6]3 years ago

4 0

Segment PT || segment QS, Given

segment PT ≅ segment QS,

∠T ≅ ∠S

Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP

So....it makes corresponding angles TPQ and SQR equal

ΔPQT ≅ ΔQRS ASA congruency

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