Question

The sum of three consecutive numbers is 600. What is the least of these three numbers?

Answer 1

Answer:

199

Step-by-step explanation:

So we have three consecutive numbers that totals 600 when added.

Let's let the first number be n.

This means that the next number is (n+1), and the subsequent number is (n+2).

This totals 600. In other words:

$(n)+(n+1)+(n+2)=600$

To solve for the integers, solve for n.

Combine like terms:

$3n+3=600$

Subtract 3 from both sides:

$3n=597$

Divide both sides by 3:

$n=199$

So, the first integer is 199.

So our sequence is: 199, 200, 201.

So, the least of the three is 199.

And we're done!

Answer 2

Answer:

199 200 201

Step-by-step explanation:

199+200+201= 600