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ryzh [129]
1 year ago
9

Type the correct answer in each box. Round the vector's magnitude to the nearest tenth.

Mathematics
1 answer:
Mama L [17]1 year ago
3 0

Component form of u is (-18,13) and The magnitude of u is 22.2

<h3>What is a vector?</h3>

A vector is a two-dimensional entity with both magnitude and direction. A vector can be visualized geometrically as a directed line segment.

The component form of a vector is an ordered pair that describes the change in x and y values

This is mathematically expressed as (Δx, Δy) where Δx=x₂-x₁ and Δy=y₂-y₁

Given ;

Initial points of the vector as (14,-6)

The terminal point of the vector is (-4,7)

Here x₁=14,x₂=-4, y₁=-6,y₂=7

The component form of the vector u is (-4-14,7--6) =(-18,13)

Finding the Magnitude of the vector

u=√(x₂-x₁)²+(y₂-y₁)²

u=√-18²+13²

u=√324+169

u=√493

u=22.2

Therefore the Component form of u is (-18,13) and The magnitude of u is 22.2

To know more about vectors follow

brainly.com/question/25705666

#SPJ1

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The clearance between a pin and the collar around it is important for the proper performance of a disc drive for small computers
hichkok12 [17]

Answer:

(a) The distribution of (Y - X) is <em>N</em> (0.001, 0.0005).

(b) The probability that the pin will not fit inside the collar is 0.023.

Step-by-step explanation:

The random variable <em>X</em> is defined as the diameter of the pin and the random variable <em>Y</em> is defined as the diameter of the collar.

The distribution of <em>X</em> and <em>Y</em> is:

X\sim N(0.525, 0.0003)\\Y\sim N(0.526, 0.0004)

The random variables <em>X</em> and <em>Y</em> are independent of each other.

(a)

Compute the expected value of (Y - X) as follows:

E(Y-X)=E(Y)-E(X)=0.526-0.525=0.001

The mean of (Y - X) is 0.001.

Compute the variance of (Y - X) as follows:

V(Y-X)=V(Y)+V(X)-2Cov(X,Y)\\=V(Y)+V(X);\ X\ and\ Y\ are\ independent\\=0.0003^{2}+0.0004^{2}\\=0.00000025

SD(Y-X)=\sqrt{0.00000025}=0.0005

The standard deviation of (Y - X) is 0.0005.

Thus, the distribution of (Y - X) is <em>N</em> (0.001, 0.0005).

(b)

Compute the probability of [(Y - X) ≤ 0] as follows:

P(Y-X\leq 0)=P(\frac{(Y-X)-\mu_{Y-X}}{\sigma_{Y-X}}\leq \frac{0-0.001}{0.0005})=P(Z

*Use a <em>z</em>-table for the probability value.

Thus, the probability that the pin will not fit inside the collar is 0.023.

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The measures of angles X and Y are the same, x degrees. The measure of angle Z is twice the measure of angle Y.
Ne4ueva [31]

Answer:

If you're trying to find the measurement of angle z then it'd be 2x degrees, since its twice that of angle y, which is x degrees

Step-by-step explanation:

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There are five sales associates at Mid-Motors Ford. The five associates and the number of cars they sold last week are: Sales As
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Answer:

a) There are 10 different samples of size 2.

b) See the explanation section

c) See the explanation section

Step-by-step explanation:

a) We need to select a sample of size 2 from the given population of size 5. We use combination to get the number of difference sample.

\{ {{5} \atop {2}} \} = \frac{5!}{2!(5-2)!} \\= \frac{5!}{2!3!} \\= \frac{120}{2*6} \\= \frac{120}{12} \\=10

b) Possible sample of size 2:

Peter Hankish 8 Connie Stallter 6 Juan Lopez 4 Ted Barnes 10 Peggy Chu 6

  1. Peter Hankish and Connie Stallter ( Mean = (8 + 6)/2 = 14/2 = 7)
  2. Peter Hankish and Juan Lopez (Mean = (8 + 4)/2 = 12/2 = 6)
  3. Peter Hankish and Ted Barnes (Mean = (8 + 10)/2 = 18/2 = 9)
  4. Peter Hankish and Peggy Chu (Mean = (8 + 6)/2 = 14/2 = 7)
  5. Connie Stallter and Juan Lopez (Mean = (6 + 4)/2 = 10/2 = 5)
  6. Connie Stallter and Ted Barnes (Mean = (6 + 10)/2 = 16/2 = 8)
  7. Connie Stallter and PeggyChu (Mean = (6 + 6)/2 = 12/2 = 6)
  8. Juan Lopez and Ted Barnes (Mean = (4 + 10)/2 = 14/2 = 7)
  9. Juan Lopez and Peggy Chu (Mean = (4 + 6)/2 = 10/2 = 5)
  10. Ted Barnes and Peggy Chu (Mean = (10 + 6)/2 = 16/2 = 8)

c) The mean of the population is:

mean = \frac{(8+6+4+10+6)}{5} \\= \frac{34}{5} \\= 6.8

Comparing the mean of the population and the sample; we can say that most of the 2-size sample have their mean higher than that of the population sample. And the variation with the mean is not much. Some sample have their mean greater than population mean, while some sample have their mean greater than the population mean.

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Is 11/16 bigger than 13/20
GenaCL600 [577]
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