Question

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?
A. 72.25 percent
B. 2.25 percent
C. 12.75 percent
D. 25.5 percent

Answer 1

A. Since the frequency of the R allele is 0.85, the frequency of the RR genotype would be 0.85^2 = 0.7225.

Answer 2

Answer:

A. 72.25 percent

Explanation:

The frequency of a genotype is calculated by the product of multiplying allele frequencies.

The R allele has a frequency of 85% (0.85), so for a homozyguous individual RR:

f(R) * f(R) = 0.85 * 0.85 = 0.7725

0.7725 * 100 = 77.25%

It is concluded that the frequency for RR genotype is 77.25%.