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olchik [2.2K]
3 years ago
5

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the

r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?
A. 72.25 percent
B. 2.25 percent
C. 12.75 percent
D. 25.5 percent
Biology
2 answers:
erica [24]3 years ago
6 0
A. Since the frequency of the R allele is 0.85, the frequency of the RR genotype would be 0.85^2 = 0.7225.
horsena [70]3 years ago
3 0

Answer:

A. 72.25 percent

Explanation:

The frequency of a genotype is calculated by the product of multiplying allele frequencies.

The R allele has a frequency of 85% (0.85), so for a homozyguous individual RR:

f(R) * f(R) = 0.85 * 0.85 = 0.7725

0.7725 * 100 = 77.25%

It is concluded that the frequency for RR genotype is 77.25%.

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