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2 years ago

Solve the equation 4(x + 5) = 9x + 4x - 34, and show your work

Mathematics

1 answer:

Alla [95]2 years ago

5 0

Answer: 4x + 20 = 13x - 34

Step-by-step explanation:

For the first one, you have to do distributive property.

4*x = 4x, 4*5 = 20

4x + 20

For the second one, you have to add the 9x + 4x.

9x + 4x = 13x

13x - 34

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Derivative of y=(3x+5)^3

UkoKoshka [18]

$\\ \sf\longmapsto \dfrac{dy}{dt}$

$\\ \sf\longmapsto \dfrac{d}{dt}(3x+5)^3$

$\\ \sf\longmapsto \{3(3x+5)\}^2$

$\\ \sf\longmapsto (9x+15)^2$

$\\ \sf\longmapsto 9x^2+2(9x)(15)+(15)^2$

$\\ \sf\longmapsto 81x^2+270x+225$

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2 years ago

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A month of the year is chosen at random. What is the probability that the month starts with the letter J or the letter M?

Harman [31]

J: 1/12
m: 1/12

i think this is the answer. hope it helps :)

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2 years ago

What the answer plz help

ratelena [41]

20 = 40e^-0.1446t
e^-0.1446t = 0.5

t = ln 0.5 / -0.1446
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2 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir

Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, we find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

$\sigma = \sqrt{484} = 22$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$5 = 1.96*\frac{22}{\sqrt{n}}$

$5\sqrt{n} = 43.12$

$\sqrt{n} = \frac{43.12}{5}$

$\sqrt{n} = 8.624$

$(\sqrt{n})^{2} = (8.624)^{2}$

$n = 74.4$

We need a sample size of at least 75.

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2 years ago

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What is the probability that a marble chosen at random is

Brums [2.3K]

Answer:

$P=\frac{6}{11}$

Step-by-step explanation:

The probability can be defined as the ratio between the possible events and the total number of outcomes.

In this case, according to the image attached, the total number of outcomes is 11, because they are 11 marbles in total.

Now, the specific event is all shaded marbles or labeled with a multiple of 3. With this specific characteristics 6 marbles, because there are 5 shaded marbles and 6 is a multiple of 3. So, the possible events are 6.

Therefore, the probability is

$P=\frac{6}{11}$

The right answer is the last choice.

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2 years ago

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