Question

=" \frac{ \sqrt{-4} }{(3+1)-(2+3i)} " alt=" \frac{ \sqrt{-4} }{(3+1)-(2+3i)} " align="absmiddle" class="latex-formula">  simplfy the expression

Answer 1

$\sqrt{-4}$ can also be written as 2i 
where i = √-1

$\frac{2i}{4-2-3i} = \frac{2i}{2-3i}$

Rationalizing denominator,

$\frac{2i(2+3i)}{(2-3i)(2+3i)} = \frac{4i-6}{4+9} = \frac{4i-6}{13}$