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Hunter-Best [27]
3 years ago
12

=" \frac{ \sqrt{-4} }{(3+1)-(2+3i)} " alt=" \frac{ \sqrt{-4} }{(3+1)-(2+3i)} " align="absmiddle" class="latex-formula">  simplfy the expression
Mathematics
1 answer:
frozen [14]3 years ago
8 0
\sqrt{-4} can also be written as 2i 
where i = √-1

\frac{2i}{4-2-3i} =  \frac{2i}{2-3i}

Rationalizing denominator,

\frac{2i(2+3i)}{(2-3i)(2+3i)} =  \frac{4i-6}{4+9} =  \frac{4i-6}{13}
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Instructions: use the ratio of a 45-45-90 triangle to solve for the variables. Leave your answers as radicals in simplest form
DIA [1.3K]

Answer:

v=14, u=14

Step-by-step explanation:

The 45-45-90 theorem states that the hypotenuse is \sqrt{2} times the bases of the triangle. So, to find one of the bases, we need to divide \sqrt{2}. Thus, \frac{12\sqrt{2} }{\sqrt{2} } = 12.

4 0
3 years ago
Maurice's teacher asked him to compare the mean and median of the data distribution explain and correct Maurice's error in compa
Dmitry_Shevchenko [17]

The first part where he mentions "The distribution is skewed right" is correct. The tail on the right hand side is pulled longer than it should be, or longer compared to the left tail. "Right skew" or "skewed right" is the same as "positively skewed". They all mean the same thing.

The portion where Maurice says "This implies that the mean is less than the median" is incorrect. This is where his error is located. The reason for the error is because it should be "The mean is greater than the median" when we have right-skewed data like this.

Here's one example to see why this is the case. Consider the distribution {1,2,3,4,5}. We can see that the median is 3 since it's directly in the center. The mean is also 3 since we add up all the values and divide by 5. Symmetric data has mean = median. Now, we'll replace the '5' with something much larger to get a large outlier. Let's say we have the set {1,2,3,4,55}. The median is still 3. The outlier doesn't pull on the median. However, the mean has changed and it is (1+2+3+4+55)/5 = 65/5 = 13. The mean went from 3 to 13. Therefore, mean > median here. The mean is affected by outliers. Think of it like the outlier is pulling on the mean in a sort of magnetic way. This outlier makes the mean larger than it should be. If the outlier is extreme enough, then it sometimes makes sense to consider the trimmed mean as opposed to the regular arithmetic mean. The trimmed mean is the mean of the main cluster of values ignoring the outlier(s).

-----------------------

To recap:

If we have right skewed data, then mean > median

As you can probably guess, if we had left-skewed data, then mean < median. In symmetric data, mean = median.

4 0
3 years ago
Please help , i know i have to use sine and cosine but i cant seem to get the right answer :)
aleksandr82 [10.1K]

Answer:

91

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Luther evaluated 2 to the power of 3 as 9 and wade evaluated 3 to the power of 2 as 9 are both students correct explain why or w
Dmitry_Shevchenko [17]

Answer:

Luther is wrong

Wade is right

Step-by-step explanation:

Luther's case 2^3 = 2x2x2 = 8

Wade's case 3^3 = 3 x 3 = 9

7 0
3 years ago
Read 2 more answers
The record low temperature in Hawaii is -0.15 times the record low temperature in Alaska. The record low temperature in Hawaii i
Luba_88 [7]

Answer:the record low temperature in Alaska = -80°F

Step-by-step explanation:

Step 1

Let the temperature in Alaska be = x

such that  the temperature in Hawaii be -0.15 times temperature in Alaska = -0.15 x.

Step 2

IF the   record low temperature in Hawaii is 12°F.

Alaska = ??

We know that

Hawaii= -0.15 x temperature Alaska ( 0.15 x)

12°F=-0.15 x temperature Alaska(x)

Temperature of Alaska, x =  12°F/-0.15

= -80°F

4 0
3 years ago
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