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pantera1 [17]
3 years ago
5

In a certain Algebra 2 class of 29 students, 5 of them play basketball and 16 of them play baseball. There are 10 students who p

lay neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Mathematics
1 answer:
kkurt [141]3 years ago
5 0
ANSWER
P(both\:sports)= \frac{2}{29}

EXPLANATION
Let the number who plays both games be
x
Then those who play only basketball
= 5 - x

and those who play only baseball
= 16 - x

We were given that 10 students play neither sports.

We can then write the following equation,

(5 - x) + x + (16 - x) + 10 = 29

This implies that,

- x + x - x = 29 - 5 - 16 - 10

This simplifies to,

- x = - 2

This gives us,

x = 2

Therefore the number of students play both basketball and baseball is 2.

The probability that a student chosen from the class plays both basketball and baseball ball

= \frac{2}{29}
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