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3 years ago

12

he table shows the number of calories in different numbers of apples. Number of Apples 3 5 8 Number of Calories 195 325 520 How

many calories are in 9 apples? Enter your answer in the box.

1 answer:

lutik1710 [3]3 years ago

7 0

Answer:

The correct answer is 585 colories. I know it is correct because I tooked the quiz.

Hope it helps! :)

You might be interested in

Write an equation for a line that passes thruogh (3,-1) and has a slope of 2

harkovskaia [24]

Answer:

y=2x−7

Step-by-step explanation:

so

formula is ( y 1 − y = m ( x 1 − x))

m is the slope

-1-y=2(3-x)

add 1 to both sides

−y−1+1=−2x+6+1

−y=−2x+7

divide both sides by -1

y=2x−7

Hope this helps

Brainliest please

Ask if u have more questions.

3 0

3 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

4 years ago

What is h(-8)=-2(-8+5)^2 +4

arlik [135]

Answer:

I got a fraction but, H= 7/4

3 0

3 years ago

Please help me pleaseee

jekas [21]

Answer: A - sin 63

Step-by-step explanation:

3 0

3 years ago

Please solve these two questions :) - Use the graphs to solve the equations provided.

harkovskaia [24]

Answer:

7.(1,0) and (-4,0)

8. (-3,0) and (-2,0)

Step-by-step explanation:

7.

When the function is equal to zero, we are looking for the zeros, or the x intercepts

Where it crosses the x axis are 1 and -4

(1,0) and (-4,0)

8. When the function is equal to zero, we are looking for the zeros, or the x intercepts

Where it crosses the x axis are -3 and -2

(-3,0) and (-2,0)

8 0

3 years ago

Read 2 more answers