Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
8
Step-by-step explanation:
First add -16 to -8.
your equation then is n=8.
You get your answer.
15:33
(Mark me the brainliest)
Answer:
x=5 2/11
Step-by-step explanation:
its either 5 2/11 or 57/11
1. 7 : 07
2. 9 : 45
3. 6
4. 2 : 25
5. 8
6. 17
