Please help I will mark brainlist

Mathematics

2 answers:

IRINA_888 [86]3 years ago

3 0

Answer:

False hope this helps

Step-by-step explanation:

Alexxandr [17]3 years ago

3 0

Answer:

I believe that it is false

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Find the minimum value of

vekshin1

Step-by-step explanation:

C=y[20]

Cy=[20] Answer is Cy=[20]

3 0

3 years ago

your job is to decide which of a set of given numbers is the smallest. how many comparisons (of 2 numbers at a time) do you have

kap26 [50]

If I have eight numbers and i am tasked to decide which of the set of given numbers is the smallest comparing 2 numbers at a time, I will have 28 comparisons in all. Trying all combinations for the first number, you have 7. Trying all combinations for the second number nit including its comparison to the first number (because it will be redundant), you will have 6 comparisons an so on. Adding it all up, you have 7+6+5+4+3+2+1=28.

7 0

3 years ago

What is 60x-150=30?<br> (This is all the info I have for this question sorry!)

QveST [7]

60x - 150 = 30
60x - 150 + 150 = 30 + 150
60x = 180
60x/60 = 180/60
x = 3

4 0

4 years ago

Help !!!<br>See question in image.<br>Please show workings .<br>

ella [17]

Answer:

$f(x) = 3 {x}^{2} \\ lim \: \frac{f(x + h) - f(x)}{h} \: \: when \: h - > 0 \\ lim \: \frac{3( x + h)^{2} - 3 {x}^{2} }{h} when \: h - > 0 \\ lim \: \frac{3( {x}^{2} + 2xh + {h}^{2}) - 3 {x}^{2} }{h} when \: h - > 0 \\ \\ lim \: \frac{3 {x}^{2} + 6xh + 3h^{2} - 3 {x}^{2} }{h} when \: h - > 0 \\ lim \: \frac{6xh + 3 {h}^{2} }{h} \: when \: h - > 0 \\lim \frac{6xh}{h} + \frac{3h^{2} }{h}when \: h - > 0 \\ lim \: 6x + 3h \: when \: h - > 0 \\ = 6x + 3(0) \\ = 6x + 0 \\ = 6x \\ \\ or \\ \frac{d(3x^{2}) }{dx} = 2 \times 3x^{2 - 1} \\ = 2 \times 3x^{1} \\ = 2 \times 3x \\ = 6x$