Question

*^%Brainliest 15 pounds Question 5 (2 points)

Answer 1

Answer:

0

Step-by-step explanation:

Separate into two parts

$\frac{4xy^{3} }{2xy^{2} } + \frac{8x^{2} {y}^{5} }{2x {y}^{2} }$

Simplify:

This is for the first fraction

$\frac{4x {y}^{3} }{2x {y}^{2} } = (4 \div 2)(x \div x)( {y}^{3} \div {y}^{2} )$

$2(1)( {y}^{3 - 2} )$

$2{y}$

Now for the second fraction:

$\frac{8 {x}^{2} {y}^{3} }{2x {y}^{2} } = ( 8 \div 2)( {x}^{2} \div x)( {y}^{5} \div {y}^{2} )$

$4( {x}^{2 - 1} )( {y}^{5 - 2} )$

$4x {y}^{3}$

Add both parts together

$2y + 4x {y}^{3}$

To turn this into the said formula, that would become:

$2 {x}^{0} {y}^{1} + 4 {x}^{1} {y}^{3}$

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1