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aliina [53]
3 years ago
10

Use the table to identify the values of p and q that should be used to factor x^2+9x-10 as (x+p)(x+q)

Mathematics
2 answers:
likoan [24]3 years ago
5 0
X^2 + 9x -10 = (x -1)(x +10) = (x +(-1)) (x + 10)
p = -1 and q  = 10
answer is A.
Misha Larkins [42]3 years ago
5 0

Answer with explanation:

\rightarrow x^2+9 x-10\\\\=x^2+10 x-x-10\\\\= x\times (x+10)-1 \times (x+10)\\\\=(x-1)(x+10)

From the table

Sum of term which contains coefficient of , x =9=-1+10

Constant term = -10= -1 × 10

⇒ (x+p)(x+q)=(x-1)(x+10)

Comparing , L HS and R HS

p= -1

q= 10

Option A:→ -1 and 10

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In 195019501950, the per capita gross domestic product (GDP) of Australia was approximately \$1800$1800dollar sign, 1800. Each y
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Answer:

The function of capita GDP is given by

G(t)= 1800(1+0.067)^t

where G(t) is in dollar and t is years after 1950.

Step-by-step explanation:

Given that,

in 1950, the per capita GDP of Australia was $1800.

The capita GDP is increased by 6.7 % per year.

In 1951, the capita GDP was increased =6.7% of $1800

The capita GDP was= $1800+ 6.7% of $1800

                                 =$1800(1+6.7%)

In 1952, the capita GDP was increased =$1800(1+6.7%)

The capita GDP was=$1800(1+6.7%)+ 6.7% of$1800(1+6.7%)

                                 =$1800(1+6.7%)(1+6.7)

                                 = $1800(1+6.7%)²

                                 =$1800(1+0.067)²

In 1952, the capita GDP was increased =$1800(1+6.7%)²

The capita GDP was=$1800(1+6.7%)²+ 6.7% of$1800(1+6.7%)²

                                 =$1800(1+6.7%)²(1+6.7)

                                 = $1800(1+6.7%)³

                                  =$1800(1+0.067)³

and so on.

The function of capita GDP is given by

G(t)= 1800(1+0.067)^t

where G(t) is in dollar and t is years after 1950.

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I need the one on the right I got the left one from my teacher ‍♀️‍♀️
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Answer:

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