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Degger [83]
3 years ago
15

Whats an expression using exponents for a times a times c times c?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0
A^2 x c^2

does that make sence but instead of the little tent you put the number small in the corner of you variable.
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A traffic helicopter descends at 127 m to be 338 m above the ground what was the original height of the helicopter let h be the
Agata [3.3K]

Answer:

Step-by-step explanation:

If the new height is 338m and the helicopter decended 127m to get to that new height then the original height is simply the sum of them both.

H = 338m + 127m

H = 465m

4 0
3 years ago
The function ​f(x)​ is the total amount spent at a store, when purchasing x items that are $5 each and the items are not taxable
Keith_Richards [23]
F(x)=5x

normal domain: all real numbers
practical domain: <span>all positive integers

</span>becasue we can substituent with any positive integer in the place of x
3 0
3 years ago
Read 2 more answers
What is the area of the figure
irinina [24]
It can’t be determined because there is too many numbers
3 0
3 years ago
What is the sequence of second differences for ax +b?
MAVERICK [17]

Answer:

ZERO

Step-by-step explanation  

Write the given function as

F(x) = ax + b

i.e Y = ax + b

now differentiate Y with respect to X

dY/dX = d (ax + b)/ dx

dY/dX = a

now again differentiate this function with respect to x

so,  d^2Y/dX^2 = d^2 (a)/dX^2

                         = 0 (ZERO)

note: differentiation of constant function is zero

4 0
3 years ago
Solve the given differential equation by using an appropriate substitution. The DE is of the form dy/dx = f(Ax + By + C), which
Mariana [72]

d<em>y</em>/d<em>x</em> = 4 + √(<em>y</em> - 4<em>x</em> + 6)

Make a substitution of <em>v(x)</em> = <em>y(x)</em> - 4<em>x</em> + 6, so that d<em>v</em>/d<em>x</em> = d<em>y</em>/d<em>x</em> - 4. Then the DE becomes

d<em>v</em>/d<em>x</em> + 4 = 4 + √<em>v</em>

d<em>v</em>/d<em>x</em> = √<em>v</em>

which is separable as

d<em>v</em>/√<em>v</em> = d<em>x</em>

Integrating both sides gives

2√<em>v</em> = <em>x</em> + <em>C</em>

Get the solution back in terms of <em>y</em> :

2√(<em>y</em> - 4<em>x</em> + 6) = <em>x</em> + <em>C</em>

You can go on to solve for <em>y</em> explicitly if you want.

√(<em>y</em> - 4<em>x</em> + 6) = <em>x</em>/2 + <em>C</em>

<em>y</em> - 4<em>x</em> + 6 = (<em>x</em>/2 + <em>C </em>)²

<em>y</em> = 4<em>x</em> - 6 + (<em>x</em>/2 + <em>C </em>)²

7 0
3 years ago
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