d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Look at the graph thoroughly .
It passes through origin and given some points
(-1,1)
(1,-1)
(2,-2)
(-2,2)
We observe that
Hence whatever the function be the result will be -x
Option D is correct
Answer:
I can only read the top 2 dimensions:
The one on the left is 32 ft^2, the one on the right is 31 ft^2
Step-by-step explanation:
left top: (8x5)-(2x4) = 32
right top: (8x4)-(1x1) = 31
left low: (10x?)-(4x7) = ?
right low: (8x?)-(2x6) = ?
The slope of a horizontal line will have a value equal to 0:
m=0
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
We have a point ( E(3,-4) ) and the slope of this line (m=0); therefore:y
y+4=0(x-3=
y+4=0
y=-4
Answer: the equation for the horizontal line that contains the point E, would be:
y=-4
