<h2>
Answer:</h2>

or
4 to the 21st over 5 to the 6th.
<h2>
Step-by-step explanation:</h2>
First, we need to write our expression. Let's do it step by step:
<u>4 to the 7th:</u>

<u>5 squared:</u>

<u>4 to the 7th over 5 squared:</u>

<u>4 to the 7th over 5 squared all raised to the 3rd power:</u>
<u>
</u>
Using the law of exponents:

Finally, the answer is 4 to the 21st over 5 to the 6th.
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
===========================================
Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
Answer:
Once upon a time, there were a two person family who lived out in the woods. The father took great care of the son. The father was a Botany, but had retired because of his age. But still he loved plants and grew a garden. The garden included Giant Bird of Paradise, Carnations, Irises, and ofc roses. He loved plants so much that he went out to dig a hole and plant different flowers and plants every spring. When the son grew older he helped the father with the garden. Two years later his son was accused of murder, but the body wasn't found. Next spring came and the father went out to dig. He couldn't Finnish it. He called his son and say he couldn't do the garden thing, because of his age. The son said don't dig there that's where he hid the bodies. The police came to dig the holes and try to find the bodies, but none of them were found. The father called the son again, and the son said thats all I can do for you right now.
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let
x----->number of games won by the football team
we know that

so

Hello,
"<" is transitive.
a<b
b<2 ==>a<b<2==>a<2