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3 years ago

Explain how to use multiplication to check the answer to a division problem

Mathematics

1 answer:

pentagon [3]3 years ago

4 0

Do the division problem.

Multiply the quotient times the divisor.

If there is a remainder, add it to the multiplication product.

Compare this answer to the dividend. They should be the same number

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Which equation can be used to determine the amount cherry juice in each mixture?

AleksandrR [38]

Answer:

c+5=5c

Step-by-step explanation:

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3 years ago

A self own company charges $40 per month +0.05 cents for each text message sent.Select expression is there a percent of cost in

kondaur [170]

<h3>The monthly cost of cell phone is A = 40 + 0.005 m</h3>

Step-by-step explanation:

The monthly fixed charges by mobile company = $40

The cost of sending each text message = 0.05 cents

Now, 100 cents = 1 dollar

⇒ 1 cent =$ $(\frac{1}{100} )$

⇒ 0.05 cent s =$ $(\frac{1}{100} \times 0.05) =0.0005$

Also, the number of text messages send = m

So, the cost of sending m text message = m x ( cost of 1 text )

= m x ( $ 0.0005) = 0.0005 m

Now, Total bill = Fixed rate + cost of m texts

⇒ A =$40 + $ 0.0005 m

Hence, the monthly cost of cell phone is A = 40 + 0.005 m

7 0

3 years ago

Solve by factoring x^2/6-x=-5/6

Lorico [155]

Answer:

x=18

Step-by-step explanation:

6 0

3 years ago

If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i

Murljashka [212]

Answer:

Step-by-step explanation:

n, n + 1, n + 2 - three consecutive integers

The equation:

138 - n = (n + 1) + (n + 2)

138 - n = n + 1 + n + 2 <em>combile like terms</em>

138 - n = 2n + 3 <em>subtract 138 from both sides</em>

-n = 2n - 135 <em>subtract 2n from both sides</em>

-3n = -135 <em>divide both sides by (-3)</em>

n = 45

n + 1 = 46

n + 2 = 47

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4 years ago

18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:

Ksenya-84 [330]

$a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}$

$S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525$

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3 years ago