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vladimir2022 [97]
3 years ago
12

You have 200 games and 300 dolls how much would it be altogether

Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0
You have 200 games and 300 dolls.

To find out the total number of games and dolls together, You have to add them.

200 + 300 = 500

Or you could add as below:

200
+300
______
500

So you have a total of 500 games and dolls.
lara [203]3 years ago
4 0
In this equation it would be 500 altogether
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Convert this into slope intercept from & provide its slope 5x-2y=4
Elden [556K]
Slope Intercept Form: y=mx+b
m= slope
b= y-intercept

5x - 2y= 4
subtract 5x from both sides

-2y= -5x + 4
divide both sides by -2

y= (-5x + 4)/-2
negative divided by negative equals a positive; positive divided by negative equals a negative

y= 5/2x - 4/2
simplify where possible
y= 5/2x - 2


ANSWER:
Slope Intercept Form: y= 5/2x - 2
Slope: 5/2

Hope this helps! :)
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"
qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that \arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)

Also, -\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)

This means our original expression is equal to:

\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]

Using the cosine addition formula, which states \cos(a+b)=\cos a \cos b-\sin a \sin b, we get this itself is equal to:

\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)

Since \sin^{2} \theta+\cos^{2} \theta=1, we know that:

\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}

3 0
2 years ago
What’s the slope of this equation
Vinvika [58]

Answer:

<em>m</em> = -2

General Formulas and Concepts:

<u>Algebra</u><em><u> </u></em><u>I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Function y = -2x + 5

<u>Step 2: Break Function</u>

Slope <em>m</em> = -2

y-intercept <em>b</em> = 5

5 0
3 years ago
Please help asap! Will give brainliest! Please answer correctly!<br> No guessing!
jok3333 [9.3K]

Answer:

Option D

Step-by-step explanation:

I solved in the picture

Hope this helps ^-^

4 0
3 years ago
Tanner has already taken 1 picture at home, and he expects to take 2 pictures during every day of vacation. How many days will T
SIZIF [17.4K]

Answer:

38 is the answer

Step-by-step explanation:

2 times 19 is 38

4 0
4 years ago
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