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Bad White [126]

3 years ago

7

A jet and a light plane leave the same airport at the same time and travel in opposite directions at 960 km/h and 560 km/h, resp

ectively. In how many hours will they be 4560 km apart?

1 answer:

alisha [4.7K]3 years ago

5 0

The jet travels a distance of

(960 km/h) <em>t</em>

after time <em>t</em>, while the light plane travels a distance of

(560 km/h) <em>t</em>

The jet is faster than the light plane, so the distance between them is

(960 km/h) <em>t</em> - (560 km/h) <em>t</em> = (400 km/h) <em>t</em>

so the time it takes for them to be 4560 km apart is

(400 km/h) <em>t</em> = 4560 km

==> <em>t</em> = (4560 km) / (400 km/h)

==> <em>t</em> = 11.4 h

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Answer:

The 95 percent confidence interval for the population mean is between 14.736 tons and 16.864 tons.

Step-by-step explanation:

We have the population's standard deviation, so we can find the normal confidence interval.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{3.8}{\sqrt{49}} = 1.064$

The lower end of the interval is the sample mean subtracted by M. So it is 15.8 - 1.064 = 14.736 tons

The upper end of the interval is the sample mean added to M. So it is 15.8 + 1.064 = 16.864 tons

The 95 percent confidence interval for the population mean is between 14.736 tons and 16.864 tons.

4 0

3 years ago

Peyton opened a savings account with $1800 that pays no interest. She deposits an

ozzi

Answer:

She should have $4200 in the account after 24 weeks.

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5 0

3 years ago

Read 2 more answers

I need help finding Angle P

Doss [256]

Hey bae use math-way it will definitely help

7 0

3 years ago

PLEASE HELP ME!!!

IgorC [24]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

so

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

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4 0

4 years ago

URGENTE, POR FAVOR

Firlakuza [10]

$\mathbf A=\begin{bmatrix}a_{1,1}&a_{1,2}\\a_{2,1}&a_{2,2}\end{bmatrix}$

$a_{i,j}=2i-j\implies\mathbf A=\begin{bmatrix}2\cdot1-1&2\cdot1-2\\2\cdot2-1&2\cdot2-2\end{bmatrix}=\begin{bmatrix}1&0\\3&2\end{bmatrix}$

Por la misma razón,

$\mathbf B=\begin{bmatrix}1-1&2-1\\1-2&2-2\end{bmatrix}=\begin{bmatrix}0&1\\-1&0\end{bmatrix}$

Entonces,

$4\mathbf A=\begin{bmatrix}4\cdot1&4\cdot0\\4\cdot3&4\cdot2\end{bmatrix}=\begin{bmatrix}4&0\\12&8\end{bmatrix}$

$\mathbf A-\mathbf B=\begin{bmatrix}1&0\\3&2\end{bmatrix}-\begin{bmatrix}0&1\\-1&0\end{bmatrix}=\begin{bmatrix}1-0&0-1\\3-(-1)&2-0\end{bmatrix}=\begin{bmatrix}1&-1\\4&2\end{bmatrix}$

$\mathbf B^\top=(b_{j,i})_{2\times2}=\begin{bmatrix}b_{1,1}&b_{2,1}\\b_{1,2}&b_{2,2}\end{bmatrix}=\begin{bmatrix}0&-1\\1&0\end{bmatrix}$

Yo no reconozco la notación "Ae"... Puedes explicarla?

$a_{1,1}\cdot b_{1,1}=1\cdot0=0$

$a_{2,2}\cdot b_{1,2}=2\cdot1=2$

6 0

3 years ago