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Pachacha [2.7K]
3 years ago
5

Which of the following rational functions is graphed below? ​

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
Can you provide a picture?
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Given: Two distinct circles that are tangent to each other at a common point. How many tangent lines can be drawn that touch bot
Zanzabum
As shown in the model below, there are three lines.

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Which sets of side lengths could form a triangle? Choose all that apply.
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What are the answer choices
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 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
3 years ago
8 is what percent of 64
Pavel [41]
<span>percent of 64 is 8 means number/100 * 64 = 8.n/100 * 64 = 8n/100 = 8/64n = 8*100/64 = 25/2 = 12.58 is 12.5% of 64</span>
3 0
3 years ago
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Order the numbers from least to greatest
const2013 [10]

Answer:

the square root of 9/4, 5/3, the square root of 5, and then 2.5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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