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Mandarinka [93]
3 years ago
5

What is an obtuse angle?

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0
An obtuse angle is an angle that is in between 90 degrees and 180 degrees. It looks like this 

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Find the first four terms of each sequence. <br><br> F(n) = 3n - 1
timofeeve [1]

Answer:

2, 5, 8, 11

Step-by-step explanation:

F(n) = 3n - 1

put n=1

F(1) = 3(1) - 1 = 2

put n=2

F(2) = 3(2) - 1 = 6 - 1 = 5

put n=3

F(3) = 3(3) - 1 = 9 - 1 = 8

put n=4

F(4) = 3(4) - 1 = 12 - 1 = 11

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Tommy the Dunker's performance on the basketball court is influenced by his state of mind: If he scores, he is twice as likely t
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What is the distance between points f and g
Vikentia [17]
There is 18 points between f and g
7 0
3 years ago
Help pls. it’s from khan academy
Nesterboy [21]
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step 1: Simplify both sides of the equation.
step 2:Subtract 2/3 from both sides.
step 3: Multiply both sides by 7/(-1).
4 0
3 years ago
4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10
Andrew [12]

Given the function f(x);

f(x)=-4x^2+4x-1

Evaluating the function f(x+h);

\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}

So;

f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1

Evaluating the second function;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}

simplifying further;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}

Therefore, we have;

undefined

7 0
1 year ago
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