Help me with my test please

An individual head of a sprinkler system covers a circular area of grass with a radius of 25 feet. the yard has 3 sprinkler head

frutty [35]

Answer:

Option D. 5890.5 feet²

Step-by-step explanation:

An individual head of a sprinkler system covers a circular are of grass with a radius of 25 feet.

Yard has three sprinkler heads that each cover circular area with no overlap.

We have to calculate the approximate area watered by these 3 sprinkler heads.

Area covered by one sprinkler = π×r² = π×(25)² = 625π feet²

Therefore area covered by three sprinkler heads = 3 × 625π = 5892.85 feet²

which matches the approximate value of Option D. 5890.5 feet²

3 0

3 years ago

Read 2 more answers

Did not mean to post and now this bubble won't go away :)

viktelen [127]

awwww..... that's what happens if you can't restrain yourself from judgment to one person . it will imprint on itself nor the sayings .

6 0

3 years ago

Read 2 more answers

You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob

Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X 0 1 2

P(X) 42% 50% 8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c) P(win first game) = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game) × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X 0 1 2

P(X) 42% 50% 8%

P(X = 0) = P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game) × P(win second game)] + [ P(win first game) × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value $\mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66$

f) Variance $\sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844$

Standard deviation $\sigma=\sqrt{variance} = \sqrt{0.3844}=0.62$

8 0

3 years ago

- 9.9t = - 9.9 <br> solve for t

vampirchik [111]

T=1

Hope that helps bud!

5 0

3 years ago

Marco wants to take a taxi cab ride if the cost to ride is 7.00 with the cost per m is 0.25 per mile and mr. o can only spend 30

77julia77 [94]

Each ride has a fixed cost of 7 and a cost that increases proportionally to the distance travelled of 0.25 per mile. Therefore the total cost of the ride is:

$\text{ cost(x)}=0.25\cdot x+7$

Where "x" is the distance in miles. Marco can only spend 30 on his ride, therefore the cost must be less or equal to that value.

$\begin{gathered} \text{ cost(x)}\leq30 \\ 0.25\cdot x+7\leq30 \end{gathered}$

We can solve the linear equation by isolating the "x" variable on the left side.

$\begin{gathered} 0.25\cdot x\leq30-7 \\ 0.25\cdot x\leq23 \\ x\leq\frac{23}{0.25} \\ x\leq92 \end{gathered}$

Marco's travel must be shorter or equal to 92 miles.

6 0

1 year ago