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Lelechka [254]
3 years ago
14

3w to the 6th power + 5w to the 5th power + 2 x w to the second power + 4

Mathematics
1 answer:
RSB [31]3 years ago
5 0

3w^6 + 5w ^5 + 2xw^2 +4 =

8w^11 + 2xw ^2 +4

i hope this the answer ur looking for.

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Which of the following terms is defined as "a point that divides a segment into two congruent segments"?
Bond [772]
I would say D midpoint! Hope this helps :)
3 0
3 years ago
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What is the length (magnitude) of the vector (5 -2) <br> a. √29<br> b. 5√5<br> c. 5<br> d.√2
malfutka [58]

Answer:

a. √29

Step-by-step explanation:

The formula for the magnitude of a vector is magnitude = sqrt(x^2 + y^2).

For vector (5, -2):

magnitude = sqrt(5^2 + -2^2)

magnitude = sqrt(25 + 4)

magnitude = sqrt(29)

Therefore, the answer is √29.

Hope this helped :D

8 0
3 years ago
I'm confused about this, please help!
Fofino [41]
D angle CDE
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7 0
3 years ago
- Let y represent the width of a rectangle and let x represent the rectangle's lengu.
valentina_108 [34]

Answer:

Length: 21 cm and Width:  6cm

Step-by-step explanation:

Let y be the width and x length of the rectangle. We know:

x = 4y -3 -------- eq. 1

54 = 2x + 2y    (Perimeter of the rectangle) ------- eq.  2

Substitute equation 1 in equation 2:

54 = 2(4y-3) + 2y\\54 = 8y - 6 + 2y\\54 + 6 = 8y + 2y\\60 = 10 y\\\\\frac{60}{10}= y\\y = 6

Using the value of y, we find x.

x = 4y - 3\\x = 4(6) -3\\x= 24 - 3\\x = 21

4 0
3 years ago
A cookie company packages its cookies in rectangular prism boxes designed with square bases that have both a length and width of
maw [93]

Answer:

h³- 8h² + 16h

Step-by-step explanation:

The problem tells us that the length and width of these boxes are both 4 inches less than the height of the box.

So if we name <u>h the height of the box</u>, the <u>width of the box would be h - 4 </u>and the <u>height of the box would be h - 4.</u>

Now, the volume  of a rectangular prism is given by V = height x width x length

So, considering the values we have in this problem we get:

V= height x width x volume

V = h (h-4)(h-4)

V= h(h-4)²

V= h (h²-8h + 16)

V = h³- 8h² + 16h

Therefore, the polynomial representing the volume of this box in terms of the height is h³- 8h² + 16h

5 0
3 years ago
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