A)
A=20(1.25^t)
C=25+10t
b)
A(4)=20(1.25^4)≈48.82≈49 alligators to nearest whole alligator
C(4)=25+10(4)=65 crocodiles.
c)
20(1.25^t)=25+10t
1.25^t=1.25+0.5t
t≈7
Answer:
The interquartile range is <em>50.</em>
Step-by-step explanation:
To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1 </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>. Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>. Therefore, <u><em>50</em></u><em> is our answer.</em>
6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°
Answer:
2
Step-by-step explanation:
Answer:
Y=1 X=0
Step-by-step explanation: