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3 years ago

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Consider the following sets. U = {all triangles} E = {x|x ∈ U and x is equilateral} I = {x|x ∈ U and x is isosceles} S = {x|x ∈

U and x is scalene} A = {x|x ∈ U and x is acute} O = {x|x ∈ U and x is obtuse} R = {x|x ∈ U and x is right} Which is a subset of I? E S A R

1 answer:

Semmy [17]3 years ago

8 0

Answer: E

Step-by-step explanation:

took a test :)

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bogdanovich [222]

Answer:

Answers are below

Step-by-step explanation:

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3 years ago

Which of the following is equal to 5^6/5^2?<br><br> 5x5x5<br> 5x5x5x5

lisov135 [29]

I hope this helps you

3 0

3 years ago

Read 2 more answers

2.8y + 6 + 0.2y = 5y -15

Olegator [25]

Simplify 2.8y + 6 + 0.2y to 3y + 6

subtract 3y from both sides

simplify 5y - 15 - 3y to 2y - 15

add 15 to both sides

simplify 6 + 15 to 21

divide both sides by 2

switch sides

Answer: y = 21/2

*in decimal form this would be 10.5

6 0

4 years ago

On the first day of June, there were about 16.78 h of daylight in a city. Five months later, there were about 6.70 h of daylig

Semmy [17]

Answer:

60.07%

Step-by-step explanation:

Decrease: 16.78 - 6.70 = 10.08

% decrease:

10.08/16.78 × 100 = 60.07151371%

4 0

3 years ago

Read 2 more answers

Solve the system. Enter the smallest x-coordinate first

pentagon [3]

$y= 3 \,\,,\,\,x= -2 \,\,and\,\, y=3\,\,,\,\, x=2$

Step-by-step explanation:

Solving the following system of equations:

$x^2-y=1\\2x^2+y^2=17$

Let

$x^2-y=1\,\,\,(1)\\2x^2+y^2=17\,\,\,(2)$

Putting value of x^2 in eq(2)

$x^2 = 1+y\\Putting\,\,value\,\,of\,\,x^2\,\,in\,\,eq(2)\\2(1+y)+y^2=17\\2+2y+y^2=17\\y^2+2y+2-17=0\\y^2+2y-15=0\\Factorizing:\\y^2-3y+5y-15=0\\y(y-3)+5(y-3)=0\\(y+5)(y-3)=0\\y+5=0 \,\,and \,\, y-3=0\\y = -5 \,\,and \,\, y=3$

Now, finding value of x

Putting y=-5

$x^2 = 1+y\\x^2=1-5\\x^2=-4\\Taking\,\,square\,\,root\\x= \pm2i$

y=-5, x= 2i and y=-5 , x= -2i

Since we need to find x and y coordinates and its value cannot be in terms of i so we will not consider these as answer

Putting y=3

$x^2 = 1+y\\x^2=1+3\\x^2=4\\Taking\,\,square\,\,root\\x= \pm2$

So, $y= 3 \,\,,\,\,x= -2 \,\,and\,\, y=3\,\,,\,\, x=2$

Keywords: system of equations

Learn more about system of equations at:

#learnwithBrainly

8 0

3 years ago