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vladimir1956 [14]

4 years ago

11

Is y=-4 a function or not a function

1 answer:

emmainna [20.7K]4 years ago

3 0

YES. It's a function.

It's the linear function. The graph is a horizontal line (look at the picture).

You might be interested in

What is the area of a circle with a circumfrerenc of 18.84 unites

son4ous [18]

Answer: The circumference should be:

A = 28.245 or A = 28.25 ( Rounded to the nearest hundredth if needed).

Step-by-step explanation:

In order to find the area of the circle, you need the equation:

$A= \frac{C^2}{4\pi }$

-With the circumference already been known, the equation would be:

$A = \frac{18.84^2}{4\pi }$

-The, solve it:

$A = \frac{18.84^2}{4\pi }$

$A = \frac{354.9456}{4\pi }$

$A = \frac{22841}{2500\pi } = 28.245$

-Round to the nearest hundredth if needed:

$A = 28.25$

6 0

3 years ago

Prove the following statement. Assume that all sets are subsets of a universal set U.

nadezda [96]

Answer:

O U ⊆ A ∪ B True

O U ⊆ A ∩ B False

O A ∪ B ⊆ U True

O B ⊆ U True

O A ⊆ U True

O A ∩ B ⊆ U True

Step-by-step explanation:

To prove the first part

$\text{If} \,\,\,\,\,\, A^{c} \subseteq B \,\,\,\,\,\text{then} \,\,\,\,\, A \cup B = U$

Remember that any set is a subset of the universal set. Therefore it is true that

$A \cup B \subseteq U$

Now, given any $x \in U$ it is true that

$x \in B \,\,\,\, \text{or} \,\,\,\, x \notin B$

Now according to the information given initially

$\text{If} \,\,\,\,\, x \notin B \,\,\,\,\, \text{then} \,\,\,\,\, x \notin A^{c}$

And then you know that

$\text{If} \,\,\,\,\, x \notin A^{c} \,\,\,\,\,\text{then} \,\,\,\,\,\,\, x \in A$

Therefore $U \subseteq A \cup B$ and using double inclusion

$U = A \cup B$ .

Now using the information just exposed

O U ⊆ A ∪ B True

O U ⊆ A ∩ B False

O A ∪ B ⊆ U True

O B ⊆ U True

O A ⊆ U True

O A ∩ B ⊆ U True

4 0

3 years ago

A coffee dispensary uses ⅘ of a barrel of coffee beans per batch of coffee they ship. Yesterday, the dispensary used 3 ⅕ of a ba

KengaRu [80]

Answer:

4 batches

Step-by-step explanation:

First, you need to convert the mix number into a single fraction:

3 1/5 = 16/5 total barrels of coffee beans used

This allows us to divide the numbers easier in the next step.

Next, because each batch uses 4/5 of a barrel of beans, you need to divide 16/5 by 4/5:

(16/5) / (4/5) = 16/4 = 4 batches

(The fives cancel out because they are the same divisor.)

I hope this helps!

-TheBusinessMan

4 0

4 years ago

What is the exact area of a circle with a radius of 6 feet? 24π square feet 36π square feet 121π square feet 144π square feet

8090 [49]

Answer:

36π

Step-by-step explanation:

The formula for the area of a circle is π times radius squared.

The radius in this case is 6, so squaring it gets us 36.

Multiplying this by π gets 36π.

5 0

4 years ago

Read 2 more answers

The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.What is

Lesechka [4]

Answer:

a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

Step-by-step explanation:

Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.

To find : What is the probability that

(a) the total gross sales over the next 2 weeks exceeds $5000;

(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?

Solution :

Let $X_1$ and $X_2$ denote the sales during week 1 and 2 respectively.

a) Let $X=X_1+X_2$

Assuming that $X_1$ and $X_2$ follows same distribution with same mean and deviation.

$E(X)=E(X_1+X_2)=E(X_1)+E(X_2)$

$E(X)=2\mu = 2(220)=4400$

$\sigma_X=\sqrt{var(X_1+X_2)}$

$\sigma_X=\sqrt{2\sigma^2}$

$\sigma_X=\sqrt{2}\sigma$

$\sigma_X=230\sqrt{2}$

So, $X\sim N(4400,230\sqrt{2})$

$P(X>5000)=1-P(X\leq5000)$

$P(X>5000)=1-P(Z\leq\frac{5000-4400}{230\sqrt{2}})$

$P(X>5000)=1-P(Z\leq1.844)$

$P(X>5000)=1-0.967$

$P(X>5000)=0.0321$

The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.

We use binomial distribution with n=3.

$P(X>2000)=1-P(X\leq2000)$

$P(X>2000)=1-P(Z\leq\frac{2000-2200}{230})$

$P(X>2000)=1-P(Z\leq-0.87)$

$P(X>2000)=1-0.1922$

$P(X>2000)=0.808$

Let Y be the number of weeks in which sales exceed 2000.

Now, $P(Y\geq 2)$

So, $P(Y\geq 2)=P(Y=2)+P(Y=3)$

$P(Y\geq 2)=^3C_2(0.8077)^2\cdot (1-0.8077)+^3C_3(0.8077)^3$

$P(Y\geq 2)=0.37635+0.52692$

$P(Y\geq 2)=0.90327$

The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

3 0

3 years ago