Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
.
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.





b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.





c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.




Answer:
x = 4
Step-by-step explanation:
The absolute value of 5x is still 5x.
5x - 2 = 18
Add 2 to both sides
5x = 20
Divide both sides by 5
x = 4
Answer:
He worked 26 hours as a security guard and 4 hours as a landscaper
Step-by-step explanation:
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
x = −
3
Step-by-step explanation:
Answer:
complementary angles, x=19
Step-by-step explanation:
since the two parts of the angle add up to 90, they are complementary angles.
you can find x by adding them and setting it equal to 90:
3x-2+2x-3 = 90
5x-5 = 90
5x = 95
x = 19