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2 years ago

What is 2/3 + 1/4please help

2 answers:

6 0

$\frac{2}{3}+\frac{1}{4}$

Re-write with a common denominator, in this case 12:

$\frac{2 \times 4}{3 \times 4}+\frac{1 \times 3}{4 \times 3}$
$\frac{8}{12}+\frac{3}{12}$

Add:
$\frac{8}{12}+\frac{3}{12} = \frac{11}{12}$

Nezavi [6.7K]2 years ago

3 0

First, we need a common denominator. The lowest number with both 3 and 4 (our current denominators) as factors is 12. To make the denominator of each fraction 12, we will use multiplication.

(2/3 * 4/4) + (1/4 * 3/3)
8/12 + 3/12

Now, we can simply add the numerators.

8/12 + 3/12 = 11/12

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The formula for the area of a trapezold with altitude k and bases m and n is A=k/2(m+n)

Ghella [55]

Answer:

$m=\frac{2A-kn}{k}$

Hence, option C is true.

Step-by-step explanation:

Given the expression

$A=\frac{k}{2}\left(m+n\right)$

Solving for 'm'

$A=\frac{k}{2}\left(m+n\right)$

Flip the equation

$\frac{k}{2}\left(m+n\right)=A$

Expanding by applying the distributive law: $a\left(b+c\right)=ab+ac$

$\frac{1}{2}km+\frac{1}{2}kn=A$

Add (-1)/2 × kn to both sides

$\frac{1}{2}km+\frac{1}{2}kn+\left(-\frac{1}{2}kn\right)=\left(-\frac{1}{2}kn\right)+A$

simplify

$\frac{1}{2}km=-\frac{1}{2}kn+A$

Divide both sides by k/2

$\frac{\frac{1}{2}km}{\frac{k}{2}}=\frac{-\frac{1}{2}kn+A}{\frac{k}{2}}$

$m=\frac{2A-kn}{k}$

Therefore,

$m=\frac{2A-kn}{k}$

Hence, option C is true.

7 0

2 years ago

How would I write the equation for this table?

Rudiy27

Answer:

Step-by-step explanation:

6 0

2 years ago

A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one

TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are $\binom44\binom{48}1=48$ possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by $\binom{13}1=13$ . So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

$\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024$

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing $\binom41\binom{48}4=778,320$ possible hands. Exactly 2 aces are drawn in $\binom42\binom{48}3=103,776$ hands. And so on. This gives a total of

$\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656$

possible hands containing at least 1 ace, and hence B occurs with probability

$\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412$

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. $P(A\cap B)=P(A)P(B)$ . This happens if

the hand has 4 aces and 1 non-ace, or
the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So $A\cap B$ consists of 96 possible hands, which occurs with probability