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IrinaVladis [17]
3 years ago
11

Owners of a local restaurant are concerned about their ability to provide quality service as they continue to grow and attract m

ore customers. They have collected data from Friday and Saturday nights, their busiest times of the week. During these time periods, about 81 customers arrive per hour for service. Given the number of tables and chairs, and the typical time it takes to serve a customer, the owners estimate they can serve, on average, about 113 customers per hour.
During these nights, are they in the zone of service, the critical zone , or the zone of non service?
A. zone of service
B. zone of non service
C. critical zone
Business
1 answer:
andrew-mc [135]3 years ago
3 0
B is the correct answer hope that helped love
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A worker received a $10,000 bonus and decided to split it among three different accounts. He placed part in a savings account pa
kotykmax [81]

Answer:

so savings = $2200

bonds = $4400

and mutual fund = $3400

Explanation:

given data

received bonus = $10,000

savings account paying = 4.5% per year

bonds paying = 5%

mutual fund that returned = 4%

income from these investments = $455

to find out

How much did the worker place in the government bonds

solution

we consider amount invested for 4.5 % is = x

and hen his investment in bonds is = 2x  for 5%

and rest is  10000- x  - 2x

that is = (10000- 3x ) for 4%

so

interest equation will be here

0.045 x + 0.05 (2x) + 0.04 (10000-3x) = 455

solve we get

x = 2200

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4 0
3 years ago
The total cost​ (in dollars) of manufacturing x auto body frames is ​C(x)=60,000+400x. ​(A) Find the average cost per unit if 20
Nesterboy [21]

Answer:

a) Average price per unit = 700

b) average marginal cost = -1.5 dollars/frame

c) For 201 frames are produced = $698.5

Explanation:

Given Data:

C(x) = 60000 + 400x

a) Average cost for 200 units:

Total Cost of 200 units will be:

C(200) = 60000 + 400(200)

C(200) = 140,000

Total Cost of 200 units = 140,000

Average price per unit = Total Cost / number of units

Average price per unit = 140,000/200

Average price per unit = 700

b) Marginal Average Cost:

We know that marginal cost = C^{'}(x)

And the average marginal cost = \frac{d}{dx} \frac{C(x)}{x}

So,

= the derivative of (\frac{60,000 + 400(x)}{x})

= the derivative of (\frac{(60,000)}{x} + 400)

= \frac{-60,000}{x^{2} } + 0

So,

average marginal cost = \frac{-60,000}{x^{2} }

at x = 200 units

average marginal cost = \frac{-60,000}{200^{2} }

average marginal cost = -1.5 dollars/frame

c) Average cost per frame if 201 frames are produced:

We already seen in the part b that, the average marginal cost is decreasing by 1.5 dollars /frame. So,

if 201 frames are produced the instead of 200 then the difference is of 1 frame and we discussed that average marginal cost of 1 frame is decreasing at 1.5 dollars per frame.

So,

As we know the average cost from part a = 700 dollars.

Therefore, for 201 item = 700 dollars -1.5 dollars

For 201 frames are produced = $698.5

5 0
3 years ago
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