Given that,
ABC and ADC are triangles.
The area of ΔADC is 52 m².
Suppose , AD is the median.
According to figure,
We need to find the area of ΔABC
Using theorem of triangle
Here, Δ ADB = Δ ADC
So, 
Put the value of Δ ADC
Hence, The area of ΔABC is 104 m².
(X - 5) (x + 5)
X^2 + 5x - 5x - 25
=X^2 -25
(3 + 8v) (3 - 8v)
9 - 24v + 24v - 64v^2
= 64v^2 + 9
Spruce tail because if you round it from the number 8 it will turn the 4 into a 5 turning it into 10.5, which is what you need
Answer:
80
Step-by-step explanation:
f(3)=4(3)^3-3(3)^2+5(3)-16
f(3)=4(3*3*3)-3(3*3)+15-16
f(3)=4(27)-3(9)+15-16
f(3)=108-27+15-16
f(3)=81+15-16
f(3)=96-16
f(3)=80
<h3><u>The x intercept is -4.</u></h3>
To find the x intercept, all we need to do is replace the value of y with 0.
2x + 4(0) = -8
Solve for x.
2x = -8
Divide both sides by 2.
x = -4.
