Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
This is the concept of trigonometry, the distance from the foot of the ladder will be given by:
tan theta=[opposite]/[adjacent]
opposite=17 ft
adjacent=x ft
theta=37°
thus
tan 37=17/x
x=17/tan 37
x=22.56 ft
=22.6 ft (to the nearest 10th of a foot)
Answer:
SA = 470 m²
volume = 494 m³
Step-by-step explanation:
<u>Individual areas</u>
Back = 4 x 19 = 76 m²
Top = 5 x 19 = 95 m²
sloped side = 5 x 19 = 95 m²
base = 8 x 19 = 152 m²
end = (4 x 5) + 1/2(3 x 4) = 26 m²
Total SA = 76 + 95 + 95 + 152 + (2 x 26) = 470 m²
<u>Volume</u>
volume = (4 x 5 x 19) + 1/2(3 x 4 x 19) = 494 m³
Answer:
Step-by-step explanation:
