Answer:
Option C,
Step-by-step explanation:
We can find the correct answer by plugging in the x and y values of a point on the graph into each option, then finding the one that gives a true statement as a result.
For example, one point on the graph is (30,4). We can substitute 30 for the x and 4 for the y in option C's equation, . Then, simplify:
4 does equal 4, so when we substitute a point from the graph into this equation, the result is a true statement. Thus, option C is the answer.
Answer:
a) Null hypothesis:
Alternative hypothesis:
b)
c)
d) If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.
Step-by-step explanation:
Data given and notation
The sample mean is given by:
And the sample deviation is:
represent the sample mean
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
z would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
Part a State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Part b Calculate the statistic
We can replace in formula (1) the info given like this:
Part c P-value
The degrees of freedom are given by:
Since is a right tailed test the p value would be:
Part d Conclusion
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.