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drek231 [11]
3 years ago
11

Hey6................​

Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0

Answer:

wa?

Step-by-step explanation:

vekshin13 years ago
5 0

Answer:

606

Step-by-step explanation:

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Factor this expression <br> 7n– 5n - 2
Airida [17]

Answer:

it is d i had the same one

Step-by-step explanation:

3 0
4 years ago
Three odd-shaped blocks of chocolate have the following masses and center-of-mass coordinates: (1) 0.310kg , ( 0.200 m, 0.320m )
Katarina [22]

Answer:

The x coordinate is 0.047m while y coordinate is 0.081 m

Step-by-step explanation:

The coordinates of the center of the mass of the system are given as follows

x_c=\dfrac{\sum_{i=1}x_im_i}{\sum_{i=1}m_i}\\y_c=\dfrac{\sum_{i=1}y_im_i}{\sum_{i=1}m_i}

So from the data

m1=0.310, x1=0.20,y1=0.320

m2=0.410,x2=0.110,y2=-0.380

m3=0.210,x3=-0.300,y3=0.630

Now by substitution of the values in the above equation

x_c=\dfrac{\sum_{i=1}x_im_i}{\sum_{i=1}m_i}\\x_c=\dfrac{x_1m_1+x_2m_2+x_3m_3}{m_1+m_2+m_3}\\x_c=\dfrac{0.310*0.2+0.410*.110+0.210*-0.3}{0.310+0.410+0.210}\\x_c=0.047m\\\\\\y_c=\dfrac{\sum_{i=1}y_im_i}{\sum_{i=1}m_i}\\y_c=\dfrac{y_1m_1+y_2m_2+y_3m_3}{m_1+m_2+m_3}\\y_c=\dfrac{0.310*0.320+0.410*-0.380+0.210*.630}{0.310+0.410+0.210}\\y_c=0.081m

So the x coordinate is 0.047m while y coordinate is 0.081 m

5 0
3 years ago
Can some one help?? Will mark brainliest!
Harlamova29_29 [7]

Answer:

x= - 1/3  or 13/3

Step-by-step explanation:

6 0
3 years ago
Find the coefficient of x of (1+2/x²) (2x-3/x)⁵
jenyasd209 [6]

First, we have

(1 + 2/x²) (2x - 3/x)⁵ = (2x - 3/x)⁵ + 2/x² (2x - 3/x)⁵

In the expansion of (2x - 3/x)⁵, there is no x² term. Each term takes the form

c (2x)^{5 - i} \left(-\dfrac3x\right)^i

where c is a binomial coefficient, and i is taken from the range {0, 1, 2, 3, 4, 5}. Looking at just the power of x in the product, we have

x^{5 - i} \left(\dfrac1x\right)^i = x^{5 - 2i}

and 5 - 2i = 1 only if i = 2. By the binomial theorem, this term is given by

\dbinom52 (2x)^{5-2} \left(-\dfrac3x\right)^2 = \dfrac{5!}{2!(5-2)!} \cdot 2^3 \cdot (-3)^2 x = 720x

In the other expansion, we have an additional factor of 1/x², so that any given them in the expansion contains a power of x of the form

\dfrac1{x^2} x^{5 - i} \left(\dfrac1x\right)^i = x^{3 - 2i}

and 3 - 2i = 1 only if x = 1. This term in the expansion is

\dfrac2{x^2} \dbinom51 (2x)^{5-1} \left(-\dfrac3x\right)^1 = \dfrac{5!}{1!(5-1)!} \cdot 2^5 \cdot (-3)^1 x = -480x

Then the coefficient of the x term in the whole expansion is 720 - 480 = 240.

8 0
3 years ago
A company has 13 employees. The company pays a monthly fee
Doss [256]

Answer:

$8,281

Step-by-step explanation:

637x13

5 0
4 years ago
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