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3 years ago

Elliot put 7 cups of tea into the pitcher shown. How many more cups of tea does he need to fill the pitcher?

Mathematics

1 answer:

sukhopar [10]3 years ago

8 0

Answer: The Answer would be 9.

Step-by-step explanation:

Since there is only 7 and the empty space is 2 cups, The answer would be 9. 7 + 2 = 9.

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Solve for y: 2(3y+5)=3(5y+1/3)

DerKrebs [107]

.93 would have to be the answer because you do the regular calculations, then you divide to find y.

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3 years ago

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a tight roll of paper, as delivered to the printer, is 60cm in diameter, and the paper is wound on to a wooden cylinder 8cm in d

Alekssandra [29.7K]

The area of the paper is the amount of space it occupies.

The length of papers around the edge is 1607680 cm

The given parameters are:

$\mathbf{d_1 = 60cm}$

$\mathbf{d_2 = 60cm + 8cm = 68cm}$

The area of the circle head is:

$\mathbf{Area = \pi \frac{d^2}{4}}$

So, we have:

$\mathbf{Area = \pi \frac{d_2^2 - d_1^2}{4}}$

Substitute known values

$\mathbf{Area = \pi \frac{68^2 - 60^2}{4}}$

$\mathbf{Area = \pi \frac{1024}{4}}$

$\mathbf{Area = 256\pi}$

The length of the paper is then calculated as:

$\mathbf{Length = \frac{Area}{0.0005}}$

This gives

$\mathbf{Length = \frac{256\pi}{0.0005}}$

$\mathbf{Length = \frac{256 \times 3.14}{0.0005}}$

$\mathbf{Length = 1607680}$

Hence, the length of papers around the edge is 1607680 cm

Read more about areas at:

brainly.com/question/2264643

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3 years ago

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Each respondent in the Current Population Survey of March 2005 was classified as employed, unemployed, or outside the labor forc

BartSMP [9]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

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3 years ago

Brainliest + 20 pts to whoever helps!

Blababa [14]

Answer:

C. 5.556

hoped this helps!

Step-by-step explanation:

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Lim<br> t—>0 1-cos(2t) / sin^2 (11t)

Nitella [24]

Answer:

2/121

Step-by-step explanation:

Hello,

Hôpital's rule will help here.

$\forall t \in \mathbb{R}^*\\\\f(t)=1-cos(2t)\text{ *** f is differentiable}\\f'(t)=2sin(2t)\\f''(t)=4cost(2t)\\f''(0)=4 \\ \\g(t)=sin^2(11t)\text{ *** g is differentiable}\\g'(t)=2sin(11t)\times 11 \times cos(11t)=2\times 11 sin(11t)cos(11t)\\\\g''(t)=2\times 11 (11cos^2(11t)-11sin^2(11t))\\g''(0)=2\times 11^2$

So the limit is 4/(2*121)=2/121

Thanks

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3 years ago