Ask question

Ask question

All categories

3 years ago

12

Michelle purchased a kids table with a square top. if the area of the square top is 400 inches, what is the length of one of the

sides?
i will mark brainliest just please i'm gonna fail fmfmcb

2 answers:

givi [52]3 years ago

7 0

Answer:

fiydy8dy8d8ydy8ddiydy8dyr68d8yd8yd86dy8d8yd86d86f8yf8yfiyfi6dy8f86fi6di6di6f58yfiigdfyifigfuditit8yd58dityofc8568d68r96r69d has been in H2g2g2hh2 for a year wtfor subscribing to the

harkovskaia [24]3 years ago

7 0

Answer:

20 cm

Step-by-step explanation:

the square root of 400 is 20

since all 4 sides are equal and the formula is area = L X B

20 x 20 is 400

You might be interested in

Pls helpppppppppppppp

bija089 [108]

Answer:

We just add 1.1 and 7.4 to get 8.5 .

Hope this helped!

7 0

3 years ago

Read 2 more answers

Slope of the line that contains (-8,2) , (7,-4)

Nezavi [6.7K]

Answer:

$\mathsf{slope=-\dfrac25}$

Step-by-step explanation:

$\mathsf{let \ (x_1,y_1)=(-8,2)}$

$\mathsf{let \ (x_2,y_2)=(7,-4)}$

$\mathsf{slope=\dfrac{y_2-y_1}{x_2-x_1}}$

$\implies \mathsf{slope=\dfrac{-4-2}{7--8}=-\dfrac25}$

7 0

3 years ago

What is the last of 24 and 72

marta [7]

The LCM of 24 and 72 is 72 :)

3 0

3 years ago

What is the value of n in the proportion below?

Illusion [34]

The answer would be 16

8 0

3 years ago

Read 2 more answers

On each turn of the knob, a gumball machine is equally likely to dispense a red, yellow, green or blue gumball, independent from

laiz [17]

Answer:

$P(R_2Y_2C_2B_2) = 0.03845$

Step-by-step explanation:

Given

$Balls = 4$ --- [R, Y, C and B]

$Turns = 8$

Required

$P(R_2Y_2C_2B_2)$

Since each of the 4 balls are equally likely, their probability is:

$P(R) = P(Y) = P(C) = P(B) = \frac{1}{4}$

From $P(R_2Y_2C_2B_2)$ , we have:

$R = Y = C = B = 2$

$Total = 8$

So, the total arrangement of the 8 balls is:

$Arrangement = \frac{8!}{2!2!2!2!}$

$Arrangement = \frac{40320}{2*2*2*2}$

$Arrangement = \frac{40320}{16}$

$Arrangement = 2520$

The individual probability of each ball, when put together is

$Probability = P(R)^2 * P(Y)^2 * P(C)^2 * P(B)^2$

$Probability = (1/4)^2 *(1/4)^2 *(1/4)^2 *(1/4)^2$

$Probability = (1/16) *(1/16) *(1/16) *(1/16)$

$Probability = \frac{1}{65536}$

Lastly:

$P(R_2Y_2C_2B_2) = Arrangement * Probability$

$P(R_2Y_2C_2B_2) = 2520 * \frac{1}{65536}$

$P(R_2Y_2C_2B_2) = \frac{2520 }{65536}$

$P(R_2Y_2C_2B_2) = 0.03845$

8 0

3 years ago