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2 years ago

Slope of the line that contains (-8,2) , (7,-4)

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

7 0

Answer:

$\mathsf{slope=-\dfrac25}$

Step-by-step explanation:

$\mathsf{let \ (x_1,y_1)=(-8,2)}$

$\mathsf{let \ (x_2,y_2)=(7,-4)}$

$\mathsf{slope=\dfrac{y_2-y_1}{x_2-x_1}}$

$\implies \mathsf{slope=\dfrac{-4-2}{7--8}=-\dfrac25}$

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Simplify: (3x2 − 5xy + 2y2) − (7x2 − 3xy − 3y2)

svlad2 [7]

Answer:

-4x² - 2xy + 5y²

Step-by-step explanation:

Step 1: Write expression

(3x² - 5xy + 2y²) - (7x² - 3xy - 3y²)

Step 2: Distribute negative

3x² - 5xy + 2y² - 7x² + 3xy + 3y²

Step 3: Combine like terms

-4x² - 2xy + 5y²

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3 years ago

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Calculate 20% of R400

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Answer:

Step-by-step explanation:

400: 100 you find 1% you multiply it by 20 and you have 20%

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2 years ago

Jack’s dog has a rectangular pen.The length is 2 feet longer than the width. The width is 6 feet. What is the distance around th

Marizza181 [45]

Answer:

L=W+X X=2 feet, W=width, L=length

if you were to solve it then you would get L=8

Step-by-step explanation:

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3 years ago

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I need help asap....................

docker41 [41]

Based on the given points, the point that is located on the y-axis is (0,7).

<h3>Which point is on the y axis?</h3>

The point that is on the y-axis should have a coordinate such that x is equal to 0.

This leads to the point being on the y-axis because the nonzero coordinate of the y axis would then have to be placed on the same axis.

The only point with a 0 coordinate is (0, 7) so this is the point that is located on the y-axis.

Find out more on points on the y-axis at brainly.com/question/4656315

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2 years ago

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given <u>indefinite integral</u>:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

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2 years ago