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pishuonlain [190]
3 years ago
15

You roll a number cube twice first roll is a four second roll I roll a even number is that a defendant or independent situation

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0
Independent because the ratio of the second cube is the same (1:6), and it isn't affected by the result of the first cube
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When solving for a variable in an equation, what must be achieved as a final answer?
photoshop1234 [79]

Answer:

D is the correct answer.

Hope it helps!!

6 0
3 years ago
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On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
3 years ago
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How do you solve 44 ÷ 0.5
jeka57 [31]

Answer:

88

Step-by-step explanation:

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5 0
4 years ago
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The depth of a lake in Lexington changes over time due to rainfall and evaporation. A few months ago, the depth was 1,300 feet.
SVETLANKA909090 [29]

Answer:

The Depth of the lake had increased by 19%.

Step-by-step explanation:

Given:

Depth of lake few months ago = 1300 ft

depth of lake currently = 1547 ft

We need to find the percent of increase in depth of lake.

Solution:

First we will find the increase in depth of lake.

Increase in depth of lake can be calculated by subtracting Depth of lake few months ago from depth of lake currently.

framing in equation form we get;

increase in depth of lake = 1547-1300= 247\ ft

Now to find the percent of increase in depth of lake we will divide  increase in depth of lake from Depth of lake few months ago and then multiply by 100.

framing in equation form we get;

percent of increase in depth of lake = \frac{247}{1300}\times 100 =  19\%

Hence the Depth of the lake had increased by 19%.

6 0
4 years ago
There are 30 students in the school chorale, and 12 of these students can stay after school today to help prepare the stage for
gtnhenbr [62]
Well it would be 12/30 but it could divide by 2 which equals 6/15 which can be divided by 3 which equals 2/5 so the answer 2/5
8 0
3 years ago
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