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3 years ago

Find the length of the missing side

Mathematics

1 answer:

faltersainse [42]3 years ago

6 0

Answer:

c = 17

Step-by-step explanation:

Since this is a right angle triangle we can use the Pythagoras theorem that states that $c^{2} = a^{2} + b^{2}$ (where c is the Solve for hypotenuse and "a" and "b" are the legs of the right angle triangle). From here we know that the answer to this question is....

$c^{2} = a^{2} + b^{2}\\c^{2} = 15^{2} + 8^{2} \\c^{2} = 225 + 64\\c^{2} = 289\\c = \sqrt{289} \\c = 17$

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3 years ago

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3 years ago

Find mZXZx(5t - 13°Y(3t+ 3)

trapecia [35]

The diagram provided is an isosceles triangle. An isosceles triangle has two sides having equal measure and two base angles also having equal measure.

From the marks on the triangle given, line ZX and line ZY are equal in length. This also means angle X and angle Y are equal in measure.

Therefore, we would have;

$\begin{gathered} 5t-13=3t+3 \\ \text{Collect all like terms and you'll have,} \\ 5t-3t=3+13 \\ 2t=16 \\ \text{Divide both sides by 2} \\ \frac{2t}{2}=\frac{16}{2} \\ t=8 \\ \text{If t=8, then} \\ 5t-13=5(8)-13 \\ 5t-13=40-13 \\ 5t-13=27 \end{gathered}$

This means angle X and angle Y both equal 27 degrees each.

Note that the sum of angles in a triangle is 180. Therefore, in triangle ZXY,

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9 months ago

Which of the statements below is true for the following set of numbers?

Taya2010 [7]

Answer:

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2 years ago

Please find the square roots of the following complex number.

Nana76 [90]

Hey there,

First, find the square root of the given equation.

$\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))$

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

$=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})$

Best of Luck!

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2 years ago