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RoseWind [281]
3 years ago
14

Please answer 2) multiple choice questions correctly I need it today please show work .

Mathematics
1 answer:
MrRissso [65]3 years ago
5 0

Answer:

Step-by-step explanation:

20. First find the values of the numbers being added.

(\frac{3}{4})^3 = \frac{27}{64}

(\frac{5}{8} )^2 = \frac{25}{64}

These numbers have a common denominator, so you can add the numerators

27 + 25 = 52

so the number comes out to \frac{52}{64}

to simplify, divide the numerator and denominator by 4.

So the final fraction becomes \frac{13}{16}

However the question doesn't have this answer and now I am confused. I assumed that the expression was r^{3}+s^{2} but the picture is a little bit blurry and I have bad eyesight so let me know if it is not. I'm too tired to delete this so next problem.

21.

4x + 8x + 7 + 4

Combine the like terms to get the expression

12x + 11 the answer is c.

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I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

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