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STatiana [176]
3 years ago
6

A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distr

ibution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
Mathematics
1 answer:
Rzqust [24]3 years ago
4 0

Answer:

The answer to the question is

The percent of the distribution is less than m + d is 84 %

Step-by-step explanation:

To solve the question we list out the variables

Percentage of distribution between m +d and m - d = 68 %

Therefore percentage that are outside the range of m + d and m - d = 32 %

For symmetry to be maintained, of the 32 % that are outside the range of m + d and m - d, 16 % are on either side of the range m + d to m - d

That is 16 % < (m-d) ↔ (m+d)< 16% total range = 100 %

Therefore the proportion of the range lesser than m+d = 100 - 16 or 84 %

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Slope: 3/2

y-intercept: 3

(The answer is B)

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3 years ago
In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
Which function represents g(x), a refection of f(x)=1/2(3)^x across the y-axis
Anon25 [30]

Answer: g(x) = (1/2)3^-x  reflection over y axis yields (-x,y)

5 0
2 years ago
What is the distance between M(9, −5) and N(−11, 10)?
lesya692 [45]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{25 \: units}}}}}

Step-by-step explanation:

Let M ( 9 , -5 ) be ( x₁ , y₁ ) and N ( - 11 , 10 ) be ( x₂ , y₂ )

<u>Finding</u><u> </u><u>the </u><u>distance </u><u>between</u><u> </u><u>these</u><u> </u><u>points</u>

\boxed{ \sf{distance =  \sqrt{ {(x2 - x1)}^{2} +  {(y2 - y1)}^{2}  } }}

\longrightarrow{ \sf{ \sqrt{ {( - 11 - 9)}^{2}  +  {(10 - ( - 5))}^{2} } }}

\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2} +  {(10 + 5)}^{2}  } }}

\longrightarrow{ \sf{ \sqrt{ {( - 20)}^{2}  +  {(15)}^{2} } }}

\longrightarrow{ \sf{ \sqrt{400 + 225}}}

\longrightarrow{ \sf{ \sqrt{625}}}

\longrightarrow{ \sf{ \sqrt{ {(25)}^{2} } }}

\longrightarrow{ \sf{25 \: units}}

Hope I helped!

Best regards! :D

7 0
3 years ago
Lines AB and CD are parallel. If the measure of angle
BARSIC [14]

Answer:

Angles W, Z, M, P are 111°

Angles Y, X, O, N are 69°

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