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3 years ago

7

The temperature is 3C at sunrise. By noon ,the temperature changes by 5C. What could be the temperature at noon?

1 answer:

kaheart [24]3 years ago

7 0

Answer:

it could either be 8C or -2C

Step-by-step explanation:

You might be interested in

Change 7/5 to a whole number

Harlamova29_29 [7]

Write it as a mixed fraction 7/5 = 1 2/5

5 0

3 years ago

Two banks are running promotions on savings accounts in anticipation of higher interest rates in the future.

chubhunter [2.5K]

Answer:

<h2>First Federal Bank is best</h2>

Step-by-step explanation:

First national bank gives:

$5,449.03 after 4 years being compounded annually at a rate of 2.15%

First federal bank gives:

$5,468.12 after 4 years at a rate of 2.25%

Please let me know if I did anything wrong. I will immediately fix my mistakes :)

4 0

2 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

2 years ago

Please help I do not know how to do right answer only.

lorasvet [3.4K]

Answer: X=100
Good luck

8 0

3 years ago

fabiana decides to save the money she is earning from her after school job for college. she makes an initial contribution of 300

Oxana [17]

Answer:

A. Total Money Contributed after n months = $\$ 3000 + \$ (500\times n)$

B. Total Money Contributed after 24 months = $\$ \ 15000$

Step-by-step explanation:

Given:

Initial contribution = $\$\ 3000$

each month contribution = $\$\ 500$

After 1 month contributed = $\$\ 3000 + \$\ 500 \times 1= \$ \ 3500$

Solving for Part A

let n be the number of months

∴ Total Contribution after n months = Initial contribution + (each month contribution $\times$ Number of months = $\$\ 3000 + \$\ 500 \times n$

Solving for Part A

Now n= 24 months

∴ Total Contribution after 24 months = $\$\ 3000 + \$\ 500 \times 24 = \$\ 3000 + \$\ 12000= \$\ 15000$

3 0

3 years ago