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Dmitrij [34]
3 years ago
6

The monthly earnings of computer systems analysts are normally distributed with a mean of $4,300. If only 1.07% of the systems a

nalysts have a monthly income of more than $6,140, what is the value of the standard deviation of the monthly earnings of the computer systems analysts?
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

800

Step-by-step explanation:

spin [16.1K]3 years ago
7 0

Answer:800

Step-by-step explanation:

Mean(\mu )=\$ 4300

and P(X>6140)=0.0107

P(X>x_0)=0.0107

P\left ( \frac{X-\mu }{\sigma}

P\left ( z

\frac{x-\mu }{\sigma}=InvNormal(0.9893)

Using Z table to get InvNormal(0.9893)=2.30

\frac{6140-4300}{\sigma}=2.30

\sigma =\frac{6140-4300}{2.30}=800

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Answer:

I think like expressions you use x or y or such many variables. you use - or + too. like (x+2)y there are parentheses too.

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2 years ago
NO SCAM LINKS OR REPORT The length of a dollar bill is 6.14 inches. Which shows a way to represent the value of the 4 in this nu
Elden [556K]

Answer:

D.

Step-by-step explanation:

The 4 is in the hundredths place, so it represents 4 hundredths, or 4 x 1/100.

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3 years ago
What is an interval scale and what is it used for?
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3 years ago
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6 0
3 years ago
Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2
Ipatiy [6.2K]

Answer:

\frac{dAB}{dt}=340 mil/h

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here.  We can use the Pythagorean theorem, so the distance between the planes will be:

AB^{2} =AO^{2}+BO^{2} (1)

AB =\sqrt{AO^{2}+BO^{2}}=

AB =\sqrt{90^{2}+120^{2}}=150 miles

If we take the derivative of the equation (1) we could find the change of the distance between planes.

2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}

2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h

\frac{dAB}{dt}=\frac{102000}{150*2}

Finally,

\frac{dAB}{dt}=340 mil/h

I hope it helps you!

6 0
3 years ago
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